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ad-work [718]
2 years ago
6

17. How long will it take for an object accelerating at a constant rate of 5 m/s to change its velocity from 0 to 6 m/s? (A) 0.6

s (B) 1.2 s (C) 2.4 s (D) 3.6 s (E) 4.8 s​
Physics
1 answer:
VikaD [51]2 years ago
8 0

Answer:

(B)

Explanation:

Time = change of velocity ÷ acceleration

= (6-0) ÷ 5

= 1.2

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calculate the pressure exerted on the floor when a elephant who weighs 6000N stands on 1 foot which has a area of 20m
Roman55 [17]

Answer:

1500n

Explanation:

5 0
3 years ago
A 4 kg bowling ball rolls at a speed of 5 m/s on the roof of a building that is 30 meters tall. What is its kinetic energy?
klasskru [66]

ans: B

Kinetic energy = \frac{1}{2} mv^{2}

= \frac{1}{2} (4)(5^{2} )

= 50J

ps. the height will only affect its potential energy, not kinetic.

3 0
3 years ago
A person 1.8m tall stands 0.75m from a reflecting globe in a garden.
Maru [420]

Answer:

1. The image of the person is 1.41 m, virtual and formed at the back of the surface of the globe.

2. The person's image is 3.38 m tall.

Explanation:

From the given question, object distance, u = 0.75 m, object height = 1.8 m, radius of curvature of the reflecting globe, r = 8 cm = 0.08 m.

f = \frac{r}{2} = \frac{0.08}{2} = 0.04 m

1. The image distance, v, can be determined by applying mirror formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

\frac{1}{0.04} = \frac{1}{0.75} + \frac{1}{v}

\frac{4}{100} - \frac{75}{100} = \frac{1}{v}

\frac{1}{v} = \frac{4 - 75}{100}

  = - \frac{71}{100}

⇒ v = -\frac{100}{71}

      = - 1.41 m

The image of the person is 1.41 m, virtual and formed at the back of the surface of the globe.

2.  \frac{image distance}{object distance} = \frac{image height}{object height}

  \frac{1.41}{0.75} = \frac{v}{1.8}

v = \frac{2.538}{0.75}

  = 3.384

v = 3.38 m

The person's image is 3.38 m tall.

6 0
3 years ago
What is the total resistance in the circuit? (include unit in answer - ohms)
solmaris [256]

Answer:60 ohms

Explanation:

R1=30 ohms

R2=15 ohms

R3=15 ohms

Let the total resistance be R

R=R1 + R2 + R3

R=30 + 15 +15

R=60

Total resistance is 60 ohms

4 0
3 years ago
Where do most stars fall on the Hertzsprung-Russell diagram?
Alex_Xolod [135]

Answer:

Most of the stars occupy the region in the diagram along the line called the main sequence. During the stage of their lives in which stars are found on the main sequence line, they are fusing hydrogen in their cores.

7 0
2 years ago
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