Answer:
Avogadro's number is 6.022×1023 molecules. With Avogadro's number, scientists can discuss and compare very large numbers, which is useful because substances in everyday quantities contain very large numbers of atoms and molecules.
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Answer:
The answer to your question is 30 ml of H₂SO₄
Explanation:
Data
the volume of H₂SO₄ = ?
[H₂SO₄] = 0.6 M
volume of NaOH = 90 ml
[NaOH] = 0.4
Process
1.- Write the balanced chemical equation
H₂SO₄ + 2NaOH ⇒ Na₂SO₄ + 2H₂O
2.- Calculate the moles of NaOH
Molarity = moles/volume
moles = Molarity x volume
-Substitution
moles = 0.4 x 0.09
-result
moles = 0.036 of NaOH
3.- Calculate the moles of H₂SO₄
1 mol of H₂SO₄ ---------------- 2 moles of NaOH
x ----------------- 0.036 moles of NaOH
x = (0.036 x 1)/2
x = 0.018 moles of H₂SO₄
4.- Calculate the volume of H₂SO₄
Volume = moles / Molarity
-Substitution
Volume = 0.018 / 0.6
-Result
Volume = 0.03 ml or 30 ml
The correct answer is 2.05 !!
Answer: Option (1) is the correct answer.
Explanation:
Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.
With increase in atomic size of the atom, there will be less force of attraction between the nucleus and the valence electrons of the atom. Hence, with lesser amount of energy the valence electrons can be removed.
When we move across a period then due to increase in force of attraction the size of atom decreases.
Thus, we can conclude that Phosphorus has a higher ionization energy than silicon because the outer orbitals of phosphorus are located closer to the nucleus than the outer orbitals of silicon.
<span>The movement of particles within a solid is extremely slow when compared to that of a gas. It is also significantly slower in movement than that of the movement found within the particles of liquid. The more movement present and the faster the movement of the particles the more space will be present between each particle. This causes the material to spread out as they become less densely packed within a solid material.</span>
