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irga5000 [103]
3 years ago
14

Under which conditions of temperature and pressure does a real gas behave most like an ideal gas

Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
4 0
At higher temperature, and lower pressure. 
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In the oxidation reduction reaction 2FeCl2 + Cl2 = 2FeCl3 what substance is reduced? What substance is oxidized?
marishachu [46]

Answer:

Iron is oxidized while chlorine is reduced.

Explanation:

The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining or losing the electrons and oxidation state of elements are changed.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reaction:

2FeCl₂  + Cl₂  →  2FeCl₃

in this reaction the oxidation state of iron is increased from +2 to +3. That's why iron get oxidized and it is reducing agent because it reduced the chlorine. The chlorine is reduced from -2 to -3 and it is oxidizing agent because it oxidized the iron.

2Fe⁺²Cl₂⁻²

2Fe⁺³Cl₃⁻³

The iron atom gives it three electrons to three atoms of chlorine and gain positive charge while chlorine atom accept the electron and form anion.

4 0
3 years ago
Enter the ionic equation, including phases, for the reaction of AgNO3(aq) with K2SO4(aq).
gogolik [260]
 The answer is 
2Ag+(aq) + SO4-2(aq) → Ag2SO4(s) 

<span>NO3- and K+ ions are spectators </span>
3 0
3 years ago
Liquid water boiling in an open pan on a stove is our system. Is the system open or closed? What boundary transfers are happenin
valina [46]

Answer:

It's an open system, tranfering heat through a rigid, diathermal wall and matter through an imaginary and permeable wall, and it is not at steady state.

Explanation:

  • An <em>open system</em> is that that interacts with its surroundings exchanging energy and matter. In an open pan with boiling water you have an open system because steam (matter) is leaving the system, as well as heat (energy) through the pan/stove.
  • A<em> boundary</em> is what separates the system from its surroundings, there are many types of boundaries, based on how they transfer energy they can be diathermal (conducting heat) or adiabatic (insulating), on their rigidity they can be rigid, flexible, imaginary or movable and based on their permeability. For the system described we have an imaginary boundary on top that is also permeable allowing matter to go out or in the system, and another wall (the stove/pan itself that is rigid and impermeable avoiding the loss of matter and diathermal, allowing the conduction of heat.
  • It is said that a system is at a<em> steady state</em> when the variables that define that system remain constant over time. In an open pan, you can't fully control those variables, you'll have matter and energy scaping from it with no way to regulate it.

I hope you find interesting and useful this information! good luck!

3 0
3 years ago
What is the net charge of C
sashaice [31]

Explanation:

Sorry, I don't know, but I can tell you that when an atom, or a body, has the same amount of positive charges (protons) and negative charges (electrons), it is said to be electrically neutral. ... The net charge corresponds to the algebraic sum of all the charges that a body possesses.

5 0
2 years ago
Read 2 more answers
What is the new pressure if the temperature outside is 296k and his weight causes the tire's volume to drop to 2.0 liters
sukhopar [10]

Question:

At standard temperature and pressure, the volume of a tire is 3.5L. What is the new pressure if the temperature outside is 296k and its weight causes the volume of the gas is 2.0 L?

Answer:

The new pressure is: 1.896 atm

Explanation:

At standard temperature and pressure, we have:

P_1 = 1atm

T_1 = 273.15k

V_1 = 3.5L

Outside, we have:

T_2 = 296k

V_2 = 2.0L

Required

Determine the new pressure

Using combined gas law, we have:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

This gives:

\frac{1 * 3.5}{273.15} =\frac{P_2*2.0}{296}

Solve for P_2

P_2 = \frac{296 * 1 * 3.5}{273.15*2.0}

P_2 = \frac{1036}{546.30}

P_2 \approx 1.896 atm

7 0
3 years ago
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