The answer is <span>the
reaction will shift to the left (toward the reactants).
Reaction is at equilibrium can be expressed as,
Reactants </span>⇄ products<span>
<span>After coming to the equilibrium, if one condition
is changed, then according to the </span>Le chatelier's Principal,<span> the system
will act to maintain the equilibrium by reducing the effect. As an example, if
we reduce the pressure, then system acts to increase the pressure to maintain
the equilibrium.</span>
<span>Likewise, if we add products into the reaction
which is in equilibrium, the system acts to reduce the effect by promoting the backward
reaction to produce reactants.</span></span>
C. The formation of precipatation
The ingredient's molecules would be more free and move faster, then the phase would change to liquid from solid.
<u>Explanation</u>:
- This task seeks to examine the knowledge of the kinetic phase and characteristics of matters.
- Here we see the chef described that the ingredient's molecules are moving in place – solid.
- On the advent of causing the ingredient to change phase by transferring energy into it – the ingredient's molecules would be more free and move faster, then the phase would change to liquid from solid.
Answer:
CaCl₂ > CH₃OH = LiCl > C₆H₁₂O₆
Explanation:
The osmotic pressure of a compound is calculated using the following expression:
π = MRT (1)
This expression is used when the substance is nonelectrolyte. If the solution is electrolyte solution then we need to count the van't hoff factor into the expression so:
π = MRTi (2)
Now, we have 4 solutions here, only two of them are electrolyte solution, this means that these solutions can be dissociated into separate ions. These solutions are LiCl and CaCl₂. It can be shown in the following reactions:
LiCl -------> Li⁺ + Cl⁻ 2 ions (i = 2)
CaCl₂ ---------> Ca²⁺ + 2Cl⁻ 3 ions (i = 3)
The methanol (CH₃OH) and glucose (C₆H₁₂O₆) are non electrolyte solutions, therefore they are not dissociated. So, let's use expression (1) for methanol and glucose, and expression (2) for the salts:
CaCl₂: π = 1 * 3 * RT = 3RT
CH₃OH: π = 2 * RT = 2RT
C₆H₁₂O₆: π = 1 * RT = 1RT
LiCl: π = 1 * 2 * RT = 2RT
Finally with these results we can conclude that the decreasing order of these solutions according to their osmotic pressures are:
<h2>
CaCl₂ > CH₃OH = LiCl > C₆H₁₂O₆</h2>
