Answer:
5.5 seconds
Step-by-step explanation:
The function that gives the height of the object after t seconds falling is:
h = -16t^2 + 484.
To find the time when the object reaches the ground, we just need to use the value of h = 0 in the equation, and then find the value of t:
0 = -16t^2 + 484.
16t^2 = 484
t^2 = 30.25
t = 5.5 seconds
So the object will reach the ground after 5.5 seconds
The potential solutions of
are 2 and -8.
<h3>Properties of Logarithms</h3>
From the properties of logarithms, you can rewrite logarithmic expressions.
The main properties are:
- Product Rule for Logarithms -

- Quotient Rule for Logarithms -

- Power Rule for Logarithms -

The exercise asks the potential solutions for
. In this expression you can apply the Product Rule for Logarithms.

Now you should solve the quadratic equation.
Δ=
. Thus, x will be
. Then:

The potential solutions are 2 and -8.
Read more about the properties of logarithms here:
brainly.com/question/14868849
Answer:
2
Step-by-step explanation:
So I'm going to use vieta's formula.
Let u and v the zeros of the given quadratic in ax^2+bx+c form.
By vieta's formula:
1) u+v=-b/a
2) uv=c/a
We are also given not by the formula but by this problem:
3) u+v=uv
If we plug 1) and 2) into 3) we get:
-b/a=c/a
Multiply both sides by a:
-b=c
Here we have:
a=3
b=-(3k-2)
c=-(k-6)
So we are solving
-b=c for k:
3k-2=-(k-6)
Distribute:
3k-2=-k+6
Add k on both sides:
4k-2=6
Add 2 on both side:
4k=8
Divide both sides by 4:
k=2
Let's check:
:


I'm going to solve
for x using the quadratic formula:







Let's see if uv=u+v holds.

Keep in mind you are multiplying conjugates:



Let's see what u+v is now:


We have confirmed uv=u+v for k=2.
To find the height of the parallelogram you would divide 6 from the area, 27, to get the answer 4.5,
So h=4.5
18 birds are left then regroup a ten 28 I hope it’ helps