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jeka57 [31]
3 years ago
6

On the island of Hawaii, Keanu notices that the sand on the beach is black, the same color as the rock formations on the island.

Keanu realizes the sand used to be part of the rock formations. How did material from the rock formations turn into sand?
a

Rays from the sun shone down on the rock, and it broke into pieces.



b

If anything were left out for a long time, it would break into small pieces.



c


The sand was formed by earthquakes, tsunamis, and other natural disasters. These disasters were strong enough to break the rock into small pieces.


d

Wind and rain interacted with the rock, breaking it into small pieces.
Chemistry
1 answer:
qwelly [4]3 years ago
5 0

Answer:

D

Explanation:

Rocks turn into sand through heat, wind, and water. D is the most plausible in this situation since it takes time to break them down into sand.

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Estimate the molecular weight of a polymer if a 100.-mL solution of 6.5 g of the polymer in toluene has an osmotic pressure of 0
MakcuM [25]
Mona le supe te gustan 
8 0
3 years ago
NiO is to be reduced to nickel metal in an industrial process by use of the reaction:NiO(s) + CO(g) <-----> Ni(s) + CO2(g)
slavikrds [6]

Answer:

The reaction will occur, in the forward direction, and NiO will be reduced to Ni

Explanation:

Step 1: Data given

Kp = 6.0 * 10²

Pressure of CO = 150 torr

Total pressure never exceeds 760 torr

Step 2: The balanced equation:

NiO(s) + CO(g) ⇆ Ni(s) + CO2(g)

Step 3: Calculate P(CO) and P(CO2)

For this equilibrium, the expression for Kp is:

Kp = P(CO2)/P(CO) = 6.0*10^2

(NiO and Ni are solids so do not change anything to the Kp

⇒ with P(CO) = 150 torr

⇒ P(CO) = 760 - 150 = 610 torr

Step 4: Calculate the reaction quotient

Q = 610/150 = 4.1

Q<<< Kp

There are more reactants than products. As a result, some of the reactants will become products, causing the reaction to shift to the right.

This means the reaction will proceed in the forward direction, and NiO will be reduced to Ni.

6 0
3 years ago
Given that the ka for hocl is 3.5 × 10–8, calculate the k value for the reaction of hocl with oh–.
Harlamova29_29 [7]
Following reaction is involved in above system
HOCl(aq)  ↔  H+(aq) + OCl-<span>(aq)
</span>OCl-(aq) + H2O(l)  ↔ HOCl(aq) + OH-<span>(aq)
</span>
Now, if the system is obeys 1st order kinetics we have
K  = [OCl-][H+<span>]/[HOCl]   ............. (1)
</span>∴ [HOCl-] / [OCl-] = [H+] (1 / 3.0 * 10-8<span>)   ............. (2)
</span>
and now considering that system is obeying 2nd order kinetics, we have
K  = [OH-][HOCl-] / [OCl-] ................. (3<span>)
</span>Subs 2 in 3 we get
K = [OH-][H+] (1 / 3.0 * 10-8<span>)
</span>we know that, [OH-][H+] = 10<span>-14

</span>∴K = 3.3 * 10<span>-7
</span>
Thus, correct answer is e i.e none of these
6 0
3 years ago
Read 2 more answers
Hydrogen produced from a hydrolysis reaction was collected over water and the following data was compiled.
Shkiper50 [21]

Answer:

  • 0.00358 mol

Explanation:

<u>1) Data:</u>

a) V = 93.90 ml

b) T = 28°C

c) P₁ = 744 mmHg

d) P₂ = 28.25 mmHg

d) n = ?

<u>2) Conversion of units</u>

a) V = 93.90 ml × 1.000 liter / 1,000 ml = 0.09390 liter

b) T = 28°C = 28 + 273.15 K = 301.15 K

c) P₁ = 744 mmHg × 1 atm / 760 mmHg = 0.9789 atm

d) P₂ = 28.5 mmHg × 1 atm / 760 mmHg = 0.0375 atm

<u>3) Chemical principles and formulae</u>

a) The total pressure of a mixture of gases is equal to the sum of the partial pressures of each gas. Hence, the partical pressure of the hydrogen gas collected is equal to the total pressure less the vapor pressure of water.

b) Ideal gas equation: pV = nRT

<u>4) Solution:</u>

a) Partial pressure of hydrogen gas: 0.9789 atm - 0.0375 atm = 0.9414 atm

b) Moles of hygrogen gas:

pV = nRT ⇒ n = pV / (RT) =

n =  (0.9414 atm × 0.09390 liter) / (0.0821 atm-liter /K-mol × 301.15K) =

n = 0.00358 mol (which is rounded to 3 significant figures) ← answer

7 0
3 years ago
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Cathode-electrolyte interphase in lithium batteries revealed by cryogenic electron microscopy. matte
Ksju [112]

Cryo-EM is used to preserve and characterize cycled positive electrodes. Under regular cycling conditions, there isn't an intimate coating layer like CEI.A small electrical short can cause a stable conformal CEI to form in place. The conformal CEI's chemistry is revealed by EELS and cryo-(S)TEM.

It has been assumed that the intimate coating layer generated on the positive electrode, known as cathode electrolyte interphase (CEI), is crucial. However, there are still numerous questions about CEI. This results from the absence of useful instruments to evaluate the chemical and structural characteristics of these delicate interphases at the nanoscale. Here, using cryogenic electron microscopy, we establish a methodology to maintain the natural condition and directly see the interface on the positive electrode.

Learn more about Cathode electrolyte interphase here:

brainly.com/question/861659

#SPJ4

4 0
1 year ago
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