Answer:
4.17e+22 atoms of tin are present in the cube
Explanation:
We don't require the size of the cube. With the mass and the molar mass of tin = 118.7 amu we can find moles of Tin. As 1 mol = 6.022x10²³ atoms we can find the number of atoms:
<em>Moles Tin:</em>
8.21g * (1mol / 118.7g) = 0.0692 moles Tin
<em>Atoms Tin:</em>
0.0692 moles Tin * (6.022x10²³ atoms / mol) =
<h3>4.17e+22 atoms of tin are present in the cube</h3>
Answer:
Br2+ 2H2O + SO2= 2HBr + H2SO4
Let's Compare the left side of the equation to the right side of the equation.
Left: Br= 2, H= 2, S= 1, O = 1+2
Right: Br=1, H= 1+2, S=1, O= 4
We can see that only S is balanced and not the other 3 elements.
I'll try to make each element balance.
For Br; I'll multiply by 2 on the left to make it equal to the right.
For H; Since the 2 for Br on the right affected also H, that H ( for HBr) Already has a 2, but then it adds with the other H2( for H2SO4) to give a total of 4 H on the right side. But then there's only 2 H on the left. so we multiply that 2 by a 2 ( which is written infront of the H2O to give a total of 4 H on the left side.
For O; Because of the 2 infront of the H2O, it affects the O in H2O..so now we have 2 O plus the 2 O ( in SO2) to give a total of 4 O which is equal to the right side.
Answer:
Given the reaction NH3 + O2 = NO + H2O, 3.25 g of NH3 is allowed to react with 3.50 g of O2. Which reactant is the limiting reagent? How many grams of H2O are formed? How much of the excess reactant remains after the reaction?
