The amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.
<h3>
What is the amount of Amoxicillin dose given to the child?</h3>
The amount of Amoxicillin dose given to the child is calculated as follows;
amount of Amoxicillin dose = weight of the child x dosage prescribed
<h3>What is the weight of the child in pounds (lb) </h3>
The weight of the child in pounds (lb) is calculated as follows;
1 lb = 0.453592 kg
85.4 lb = ?
= 85.4 x 0.453592 kg
= 38.74 kg
amount of Amoxicillin dose = 38.74 kg x 45 mg/kg
amount of Amoxicillin dose = 1,743.3 mg
Thus, the amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.
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The complete question is below:
A 85.4 lb child has a Streptococcus infection. Amoxicillin is prescribed at a dosage of 45 mg per kg of body weight per day given b.i.d. Calculate the daily dose of the child.
Answer:
Explanation:
HA(aq)+H2O(l)⟺H3O+(aq)+A−(aq)(1)
you need to solve for the Ka value. To do that you use
Ka=[H3O+][A−][HA](2)
Another necessary value is the pKa value, and that is obtained through pKa=−logKa
The procedure is very similar for weak bases. The general equation of a weak base is
BOH⟺B++OH−(3)
Solving for the Kbvalue is the same as the Ka value. You use the formula
Kb=[B+][OH−][BOH](4)
The pKb value is found through pKb=−logKb
The Kw value is found withKw=[H3O+][OH−].
Kw=1.0×10−14(5)
Answer:loko2020 I’m stupid I don’t know no answers sorry
Explanation:xd
261.162 grams. Use the equation n=M÷Mr.
