Answer:
<1 ,1>..., square root of two
Step-by-step explanation:
Component of vector PQ...,
; Q - P...where you subtract the x coordinate of Q by the x coordinate of P and the same for the y coordinate
; <(6-5),(9-8)>
; < 1,1 >
And the magnitude of PQ...,
;square root of( 1^2 + 1^2 )
;square root of 2
Answer:
range = {11,-1,-4,-13}
Step-by-step explanation:
domain is "input" range is "output"
just "plug" {-3, 1, 2,5} into -3x + 2 one at a time
Is this the image? If so, sorry I can't do this lol
Answer:
7
Step-by-step explanation:
Answer:
c, e, f, and i
Step-by-step explanation:
a. is bounded above at y = 1 and below at y = 0
b. is unbounded both above and below
c. is bounded below at y = 0 and unbounded above
d. is unbounded both above and below
e. is bounded below at y = 0 and unbounded above
f. is bounded below at y = 0 and unbounded above
g. is bounded below at y = 0 and bounded above at y = 1
h. is unbounded both above and below
i. is bounded below at y = 0 and unbounded above
j. is unbounded both above and below
