For this case we have the following function:
f (x) = x ^ 5
We apply the following transformations:
reflect over the y axis:
f (x) = (- x) ^ 5
shift 1 unit left:
f (x) = (- x + 1) ^ 5
vertically compress by 1/3:
f (x) = (1/3) (- x + 1) ^ 5
Answer:
A function that results after applying the sequence of transformations is:
f (x) = (1/3) (- x + 1) ^ 5
Dividing a whole number and an improper fraction seems tricky, but it just has one or two more steps than the normal process. First, convert the whole number "9" into a fraction by giving it a denominator of "1". It should look like 9/1. Now that both numbers are converted into like formats (improper fractions), you should have 9/1 divided by 5/3.
Second, flip 5/3 over into 3/5 - this is the "reciprocal". Now you have 9/1 divided by 3/5. It's just a matter of multiplying across the math sentence. Multiply the numerators (9x3) and the denominators (1 x 5). Your new fraction should be 27/5. This is your answer in the improper fraction format.
You can create other formats depending on the expected answer. For a mixed number, "divide your fraction UP" (27 divided by 5) which gives you 5 and 2/5. This can be further converted into 5.4 if you need your answer in decimal form.
Answer:
The new price is 45.90
Step-by-step explanation:
The original price is 51
Find the discount of 10 %
51*10%
51*.10
5.1
Subtract this from the original price
51- 5.1
45.9
The new price is 45.90
203 is the answer there you go
Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:
</span>x^2 + 2x + 4= 0. "Completing the square" seems to be the easiest way to go here:
rewrite x^2 + 2x + 4 as x^2 + 2x + 1^2 - 1^2 = -4, or
(x+1)^2 = -3
or x+1 =i*(plus or minus sqrt(3))
or x = -1 plus or minus i*sqrt(3)
This problem, like any other quadratic equation, has two roots. Note that the fourth possible answer constitutes one part of the two part solution found above.
