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vitfil [10]
3 years ago
11

Saeed moves 50 m east then 65 m south to reach the garden. What is the displacement of Saeed?​

Physics
1 answer:
vampirchik [111]3 years ago
4 0

Answer:

82.01m

Explanation:

Using the formula:

R^2=A^2+B^2

R= √ A^2+B^2

Where R= displacement

A=50m

B=65m

R= √ 50^2+65^2

R= √ 2500+4225

R= √ 6725

R=82.01m

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Answer:

(a), The SSD will be 723.9 ft.

(b-1), The SSD will be 620.2 ft.

(b-2), The SSD will be 723.91>SSD>620.2

(c), The SSD will be 910.5 ft.

Explanation:

Given that,

Speed = 70 mph

Suppose, a perception reaction time of 2.5 sec and the coefficient of friction is 0.35

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Using formula of SSD

SSD=1.47\times v\times t+\dfrac{v^2}{30\times(f\pm g)}

Where, v = speed of vehicle

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f = coefficient of friction

g = gradient of road

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Then, the stopping sight distance will be

SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35)}

SSD=723.9\ ft

(b-1). If the gradient of road is 0.1

Then, the stopping sight distance will be

SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35+0.1)}

SSD=620.2\ ft

(b-2). If the grade continuously decrease then the SSD will be increase.

But if the grade is increase then the SSD will be decrease and for flat grade the SSD will be more.

So, The SSD will be 723.91>SSD>620.2

(c). When the vehicle is traveling downhill on a roadway of constant grade then the vehicle take will be more SSD

So, The SSD will be

SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35-0.1)}

SSD=910.5\ ft

Hence, (a), The SSD will be 723.9 ft.

(b-1), The SSD will be 620.2 ft.

(b-2), The SSD will be 723.91>SSD>620.2

(c), The SSD will be 910.5 ft.

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If 34.7 g of O2 reacts with iron to form 79.34 g of iron oxide, how much iron was used in the reaction?
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Thus 44.64 g of iron was used in the reaction

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3 years ago
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