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uranmaximum [27]
2 years ago
9

If you make a solution using 1.0 mol KBr in 1.0 kg water, how will the vapor pressure of this solution compare to the vapor pres

sure of a solution made from 1.0 mol sucrose in 1.0 kg water?
a) it will be half as large
b) it will be the same
c) it will be twice as large
d) it will be four times as large
Chemistry
2 answers:
____ [38]2 years ago
5 0

Answer:

it will be twice as large

Gennadij [26K]2 years ago
5 0

Answer: a. it will be half as large

Explanation:

You might be interested in
. Through what three mechanisms do gamma rays interact with matter?
siniylev [52]

Answer:

Photoelectric effect, pair production and Compton scattering

Explanation:

Gamma rays, having no charge, can be slowed slowly by ionization as a material passes through. They suffer other mechanisms that eventually make them disappear, transferring their energy, they can cross several centimeters of a solid, or hundreds of meters of air, without undergoing any process or affecting the material they cross. Then they suffer one of the three effects and deposit much of their energy there. The three mechanisms of interaction with matter are: the photoelectric effect, the Compton effect and the production of pairs.

The photoelectric effect is that the photon meets an electron in the material and transfers all its energy, disappearing the original photon. The secondary electron acquires all the energy of the photon in the form of kinetic energy, and is sufficient to separate it from its atom and convert it into a projectile. This is stopped by ionization and excitation of the material

In the Compton effect the photon collides with an electron as if it were a clash between two elastic spheres. The secondary electron acquires only part of the energy of the photon and the rest takes it with another photon of lesser energy and diverted.

When an energy photon approaches the intense electric field of a nucleus, the production of pairs can happen. In this case the photon is transformed into an electron positron pair. Since the sum of the mass of the pair is 1.02 MeV, it cannot happen if the photon's energy is less than this amount. If the energy of the original photon is greater than 1.02 MeV, the surplus is distributed by the electron and the positron as kinetic energy, and the material can be ionized. The positron at the end of its path forms a positronium and then annihilates producing two annihilation photons, 0.51 MeV each.

3 0
3 years ago
How would you prepare 500 ml of a .50m solution of naoh from a 2 m stock solution
Bad White [126]

Explanation:

i.e M = m/V(L)

M= Molarity of substance

m = number of moles of substance (i.e solute)

V(L) = volume of solution in Litres

So talking about our question molarity should be 0.5 M,volume should be 0.1 L , and we should know that Molar Mass of NaOH is 40 because Atomic mass of Sodium i.e (Na known as Natrium) is 23,Atomic mass of Oxygen (O) is 16 and Atomic mass of Hydrogen is 1.

Adding them all up gives Molecular mass of NaOH as 40

So if we solve above equation we get no of moles of NaOH present in 0.1 litres of solution

Let’s do that math

Rearranging equation we get m=M×V(L) i.e m= 0.5×0.1 =0.05. So 0.05 moles of NaOH are present in 100 ml of 0.5 Molar solution

Now we also know that to find no of moles of a substance we have a formula and it is m=W/Mw where

m = no of moles of a substance

W = Mass of substance

Mw = Molecular weight of the substance

So substituting all values and rearranging equation we get mass of NaOH as

W=m×Mw = 0.05×40=2 grams

Hence we found the required mass of NaOH as 2 grams.

Now talking about shortcut

we know as explained above M=m/V(L) and m=W/M

Substituting value of m(no of moles) in M=m/V(L) we get M=WMw×V(L)

Try substituting the values yourself and get the answer

Note :: The value of Volume should always be substituted in terms of Litre only. That is the reason i used the letter (L) at all the places with V

So thats all get the answer and comment any other problems below

Hope you got your problem solved

Thanks!!!

7 0
3 years ago
Magnesium hydroxide is used as an antacid in milk of magnesia and reacts with hydrogen chlrode in the stomach to form water and
8_murik_8 [283]
Mg(OH)2 +2HCl---> MgCl2+2H2O
3 0
3 years ago
Consider the following reaction where K. = 9.52 10 2 at 350 K.
Harman [31]

Answer:

The correct answer is A :))

3 0
2 years ago
The titration of Na2CO3 with HCl has the following qualitative profile: a. Identify the major species in solution at points A-F.
exis [7]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.

a) We need to find the major species from A to F.

Major Species at A:

1. Na_{2} CO_{3}

Major Species at B:

1. Na_{2} CO_{3}

2. NaHCO_{3}

Major Species at C:

1. NaHCO_{3}

Major Species at D:

1. NaHCO_{3}

2. H_{2}CO_{3}

Major Species at E:

1. H_{2}CO_{3}

Major Species at F:

1. H_{2}CO_{3}

b) pH calculation:

At Halfway point B:

pH = pKa_{1} + log[CO_{3}.^{-2}]/[HCO_{3}.^{-1}]

pH = pKa_{1} = 6.35

Similarly, at halfway point D.  

At point D,

pH = pKa_{2} + log [HCO_{3}.^{-1}]/[H2CO_{3}]

pH = pKa_{2} = 10.33

8 0
3 years ago
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