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galben [10]
3 years ago
9

What happens to the force between two charged particles if the distance between them is cut in fourth?

Physics
2 answers:
dlinn [17]3 years ago
8 0

Answer: The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if the distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled.

Explanation: hope i helped c;

JulsSmile [24]3 years ago
6 0

What happens to the force between two charged particles if the distance between them is cut in fourth is that the force between the two charges is directly proportional to the product of the charges and proportional to the square of the distance between them.

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When a satellite is in orbit around the earth the force of gravity on the satellite-
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Answer:

Is always towards the center of the Earth

Explanation:

As a satellite moves around the Earth in a circular orbit, the direction of the force of gravity is always towards the center of the Earth. At an altitude of 100 km, you would be so high that you would see black sky and stars if you looked upwards.

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Which statement about two objects having the same momentum is true?
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Answer:

The product of mass X velocity is the same for both

Explanation:

The momentum of a body is the product of its mass and velocity.

  Momentum  = mass x velocity

Two objects having equal momentum will have the same for the product of their mass and velocity.

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7 0
3 years ago
2. Which of the following is NOT true of work?
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Answer:

D

Explanation:

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3 years ago
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Like the filters falling through the air, a car on the freeway represents an object with a high Reynolds number traveling throug
Goshia [24]

Answer:

ΔF=125.22 %

Explanation:

We know that drag force on the car given as

F_D=\dfrac{1}{2}\rho C_DA v^2

C_D=Drag coefficient

A=Projected area

v=Velocity

ρ=Density

All other quantity are constant so we can say that drag force and velocity can be given as

\dfrac{F_D_1}{F_D_2}=\dfrac{v_1^2}{v_2^2}

Now by putting the values

\dfrac{F_D_1}{F_D_2}=\dfrac{v_1^2}{v_2^2}

\dfrac{F_D_1}{F_D_2}=\dfrac{50^2}{75^2}

\dfrac{F_D_1}{F_D_2}=0.444

Percentage Change in the drag force

\Delta F=\dfrac{F_D_2-F_D_1}{F_D_1}\times 100

\Delta F=\dfrac{F_D_2-0.444F_D_2}{0.444F_D_2}\times 100

\Delta F=\dfrac{1-0.444}{0.444}\times 100

ΔF=125.22 %

Therefore force will increase by 125.22  %.

3 0
3 years ago
A woman has a mass of 55kg on earth, what is her mass on the moon​
KengaRu [80]

Answer:

55 kg

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Mass does not change and is not dependant on gravity. So even though your weight will be less on the moon your mass won't change.

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