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galben [10]
3 years ago
9

What happens to the force between two charged particles if the distance between them is cut in fourth?

Physics
2 answers:
dlinn [17]3 years ago
8 0

Answer: The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if the distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled.

Explanation: hope i helped c;

JulsSmile [24]3 years ago
6 0

What happens to the force between two charged particles if the distance between them is cut in fourth is that the force between the two charges is directly proportional to the product of the charges and proportional to the square of the distance between them.

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Calculate the mean free path of air molecules at a pressure of 7.00×10^−13 atm and a temperature of 303 K . (This pressure is re
Grace [21]

Answer:

82.8986 km

Explanation:

Given:

Pressure = 7.00×10⁻¹³ atm

Since , 1 atm = 101325 Pa

So, Pressure = 7.00×10⁻¹³×101325 Pa = 7.09275×10⁻⁸ Pa

Radius = 2.00×10⁻¹⁰ m

Diameter = 4.00×10⁻¹⁰ m (2× Radius)

Temperature = 303 K

The expression for mean free path is:

\lambda (Mean\ free\ path)=\frac {K (Boltzmann\ Constant)\times Temperature}{\sqrt {2}\times \pi\times (Diameter)^2\times Pressure}

Boltzmann Constant = 1.38×10⁻²³ J/K

So,

\lambda (Mean\ free\ path)=\frac {1.38\times 10^{-23}\times 303}{\sqrt {2}\times \frac {22}{7}\times (4.00\times 10^{-10})^2\times 7.09275\times 10^{-8}}

<u>Mean free path = 82.8986×10³ m = 82.8986 km</u>

4 0
4 years ago
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Nesterboy [21]
For the first one it’s the guh sound
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6 0
3 years ago
The start-up procedure for a batch reactor includes a heating step where the reactor temperature is gradually heated to the nomi
qwelly [4]
Solution: 
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• Taking the Laplace Transform: 
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7 0
3 years ago
Bob is studying waves in science and learns that the energy of a wave is directly proportional to the square of the waves amplit
Mrrafil [7]
For a simple harmonic motion energy is given with:
E=\frac{1}{2}kA^2
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Let's calculate the energy of the wave using two different amplitudes given in the problem:
E_1=\frac{1}{2}k(1)^2=\frac{1}{2}k\\E_2=\frac{1}{2}k(2)^2=\frac{4}{2}k=2k\\
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6 0
3 years ago
Read 2 more answers
What is the speaker’s power output if the sound intensity level is 102 dBdB at a distance of 25 mm ? Express your answer to two
lesya [120]

Answer:

Power  = 124.50 W

Explanation:

Given that:

The Sound intensity of a speaker output is 102 dB

and the distance r = 25 m

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\beta (dB)= 10 \  log_{10 } (\dfrac{I}{I_o})

where;

the threshold of hearing   I_o = 10^{-12} (W/m^2)

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10^{10.2} =  \dfrac{I}{10^{-12}}

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I = 0.01585 W/m²

If we recall, we know remember that ;

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Power  = 124.50 W

7 0
3 years ago
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