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3 years ago

What happens to the force between two charged particles if the distance between them is cut in fourth?

2 answers:

8 0

Answer: The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if the distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled.

Explanation: hope i helped c;

JulsSmile [24]3 years ago

6 0

What happens to the force between two charged particles if the distance between them is cut in fourth is that the force between the two charges is directly proportional to the product of the charges and proportional to the square of the distance between them.

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Which of the following is the most effective way for humans to reduce biodiversity loss?

ANTONII [103]

Answer:

Creating large preserves in biodiversity hotspots

Explanation:

In order to preserve the biodiversity hotspots, humans must create biodiversity hotspots which are regions that will nurture, preserve and protect the species from the danger of going extinct in the wild or being hunted by other predators or men.

There will help protect them from dangers and improve the biodiversity of the planet. It will add to the ecological productivity of the environment.

6 0

3 years ago

True or false? Scientific laws can be expressed through a law that relates several variables.

Marina86 [1]

Answer:

True

Explanation:

Scientific laws are often written as expressions that contains variables and are laws that are binding themselves.

In science, laws are natural phenomenon that draws from careful observations that holds through following a series of detailed study. Within the range of assumed parameters, a law will always hold true.

Most laws in science are denoted using mathematical variables which helps to interpret them.

The variables shows the relationship between the different parts of the law.

For example, Newton's law of universal gravitation is expressed mathematically as shown below;

F = $\frac{G m_{1} m_{2} }{r^{2} }$

where G, m and r are all variables.

G is the universal gravitation constant

m is mass

r is the distance between them.

F is the gravitational force.

Most scientific laws are often expressed in this format.

5 0

3 years ago

Consider your moment of inertia about a vertical axis through the center of your body, both when you are standing straight up wi

jeka94

Answer:

I₁ / I₂ = 1.43

Explanation:

To find the relationship of the two inertial memits, let's calculate each one, let's start at the moment of inertia with the arms extended

Before starting let's reduce all units to the SI system

d₁ = 42 in (2.54 10⁻² m / 1 in) = 106.68 10⁻² m

d₂ = 38 in = 96.52 10⁻² m

The moment of inertia is a scalar quantity for which it can be added, the moment of total inertia would be the moment of inertia of the man (cylinder) plus the moment of inertia of each arm

I₁ = I_man + 2 I_ arm

Man indicates that we can approximate them to a cylinder where the average diameter is

d = (d₁ + d₂) / 2

d = (106.68 + 96.52) 10-2 = 101.6 10⁻² m

The average radius is

r = d / 2 = 50.8 10⁻² m = 0.508 m

The mass of the trunk is the mass of man minus the masses of each arm.

M = M_man - 0.2 M_man = 80 (1-0.2)

M = 64 kg

The moments of inertia are:

A cylinder with respect to a vertical axis: Ic = ½ M r²

A rod that rotates at the end: I_arm = 1/3 m L²

Let us note that the arm rotates with respect to man, but this is at a distance from the axis of rotation of the body, so we must use the parallel axes theorem for the moment of inertia of the arm with respect to e = of the body axis.

I1 = I_arm + m D²

Where D is the distance from the axis of rotation of the arm to the axis of the body

D = d / 2 = 101.6 10⁻² /2 = 0.508 m

Let's replace

I₁ = ½ M r² + 2 [(1/3 m L²) + m D²]

Let's calculate

I₁ = ½ 64 (0.508)² + 2 [1/3 8 1² + 8 0.508²]

I₁ = 8.258 + 5.33 + 4.129

I₁ = 17,717 Kg m² / s²

Now let's calculate the moment of inertia with our arms at our sides, in this case the distance L = 0,

I₂ = ½ M r² + 2 m D²

I₂ = ½ 64 0.508² + 2 8 0.508²

I₂ = 8,258 + 4,129

I₂ = 12,387 kg m² / s²

The relationship between these two magnitudes is

I₁ / I₂ = 17,717 /12,387

I₁ / I₂ = 1.43

3 0

3 years ago

Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller

Travka [436]

Answer:

Explanation:

Given that,

Small wheel applied force

F₁ = 50N

Small wheel radius

r₁ = 18cm

Bigger wheel radius.

r₂ = 29cm

Bigger wheel applied force

F₂ =?

Since the combination of those forces did not cause the wheel to rotate,

Then, Στ = 0

F₁•r₁ —F₂•r₂ =

50×18 — 29F₂ = 0

900 = 29F₂

F₂ = 900 / 29

F₂ = 31.03 N

The pulling force applied at the larger wheel is 31.03N

8 0

4 years ago

A radio tower emits energy in the form of waves. These waves travel great distances. Some of them even leave Earth and travel

Elena-2011 [213]

Light because it is an electromagnetic wave and they can travel through the vacuum in outer space.

3 0

3 years ago

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