Q= mcΔT
Where Q is heat or energy
M is mass, c is heat capacitance and t is temperature
You have to convert Celsius into kelvin in order to use this formula I believe
Celsius + 273 = Kelvin
21 + 273 = 294K
363 + 273 = 636K
Now...
Q= (0.003)(0.129)(636-294)
Q= 0.132 J if you are using kilograms, in terms of grams which seems more appropriate the answer would be 132J of energy.
The potential difference,electric current ,resistance and new electric current will be 12 V,4 A,3 Ω,2 A.
<h3>What is resistance?</h3>
Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.
The energy in terms of the charge and potential difference is;
E= qV
60=5 C × V
V= 12 V
The electric current is found as;
![\rm I= \frac{q}{t} \\\\ I= \frac{5}{1.25}\\\\ I=4 \ A](https://tex.z-dn.net/?f=%5Crm%20I%3D%20%5Cfrac%7Bq%7D%7Bt%7D%20%5C%5C%5C%5C%20I%3D%20%5Cfrac%7B5%7D%7B1.25%7D%5C%5C%5C%5C%20I%3D4%20%5C%20A)
From the ohm's law;
V=IR
12=4 ×R
R=3Ω
If the voltage is constant and the resistance is doubled, then the new electric current is half of the previous condition;
![\rm I'=\frac{I}{2} \\\\ I'=\frac{4}{2} \\\\\ I'=2 \ A](https://tex.z-dn.net/?f=%5Crm%20I%27%3D%5Cfrac%7BI%7D%7B2%7D%20%5C%5C%5C%5C%20I%27%3D%5Cfrac%7B4%7D%7B2%7D%20%5C%5C%5C%5C%5C%20I%27%3D2%20%5C%20A)
Hence, the potential difference,electric current ,resistance and new electric current will be 12 V,4 A,3 Ω,2 A.
To learn more about the resistance, refer to the link;
brainly.com/question/20708652
#SPJ1
The specific gravity of the object’s material is 5.09.
<h3>To calculate the specific gravity of the object:</h3>
Weight difference = 9 - 7.2 = 1.8 N = Buoyant force of water
Buoyant Force in water(Fb) = density of water x g x volume of the body(Vb)
1.8 = 1000 x 9.81 x Vb
Vb = 1.8/9810 cubic meter
Now, in the air;
Weight of body = mg = 9 N
Mass of body,m = 9/9.81 Kg
So,
Density of body = m/ Vb
= 9/9.81 ÷ 1.8/9810
= 5094.44 kg per cubic meter
The specific gravity of body = density of body ÷ density of water
= 5094.44 ÷ 1000
= 5.09
Therefore, Specific gravity of body = 5.09
Learn more about Specific gravity here:
brainly.com/question/13258933
#SPJ4