Answer:
the angular acceleration of the gate is approximately 1.61 ![\frac{rad}{s^2}](https://tex.z-dn.net/?f=%5Cfrac%7Brad%7D%7Bs%5E2%7D)
Explanation:
Recall the formula that connects the net torque with the moment of inertia of a rotating object about its axis of rotation, and the angular acceleration (similar to Newton's second law with net force, mass, and linear acceleration):
![\sum \tau_1=I\,\alpha](https://tex.z-dn.net/?f=%5Csum%20%5Ctau_1%3DI%5C%2C%5Calpha)
In our case, both forces contribute to the same direction of torque, so we can add their torques up and get the net torque on the gate:
![\tau_{net}=(20*2+30*3.5) \,N\,m=145\,\,N\,m](https://tex.z-dn.net/?f=%5Ctau_%7Bnet%7D%3D%2820%2A2%2B30%2A3.5%29%20%5C%2CN%5C%2Cm%3D145%5C%2C%5C%2CN%5C%2Cm)
Now we use this value to obtain the angular acceleration by using the given moment of inertia of the rotating gate:
![\sum \tau_1=I\,\alpha\\145\,\,N\.m=(90\,\,kg\,m^2)\,\alpha\\\alpha= \frac{145}{90} \frac{rad}{s^2} = 1.61\, \frac{rad}{s^2}](https://tex.z-dn.net/?f=%5Csum%20%5Ctau_1%3DI%5C%2C%5Calpha%5C%5C145%5C%2C%5C%2CN%5C.m%3D%2890%5C%2C%5C%2Ckg%5C%2Cm%5E2%29%5C%2C%5Calpha%5C%5C%5Calpha%3D%20%5Cfrac%7B145%7D%7B90%7D%20%5Cfrac%7Brad%7D%7Bs%5E2%7D%20%3D%201.61%5C%2C%20%5Cfrac%7Brad%7D%7Bs%5E2%7D)
Answer with explanation:
Electronegativity is a property that enables atoms to attract bonding electrons to each other.
The higher the electronegativity, the greater an atom's attraction for electrons.
Answer:
a. How much force is required to lift a box of weight 100 N upwards with a constant acceleration of 6.0 m/s2?
b. How much upwards force is required to lower the same box with a downward acceleration of 3.0 m/s2?
a. As the box weighs 100 N, its mass is 100 N / 9.8 ms-2 = 10.2 kg. To have an upward acceleration of 6.0 m/s2, there must be a net upward force of F =ma = 10.2 kg x 6.0 m/s2 = 61.2 N. The total upward force must be equal have a magnitude to overcome the downward force of gravity and to provide for the upward acceleration Ftotal up = 100 N + 61.2 N = 161.2 N.
b. There must be a net downward force F = ma = 10.2 kg x 3.0 m/s2 = 30.6 N upward. There must be an upward force to counteract the downward force of gravity so that the resultant will be 30.6 N. The equation necessary for this is 100 N - upward force = 30.6 N. Solving for the upward force gives 69.4 N.
Explanation:
Oil is a lubricant which helps increase friction. when u spread sand on a place where oil is spilled the sand reduces friction between road and vehicle tire. the vehicle wont skid.