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vodomira [7]
4 years ago
13

Write an expression for the magnitude of the normal force, fn, acting on the block, in terms of f2 and the other variables of th

e problem. assume that the surface it rests on is rigid.
Physics
1 answer:
mario62 [17]4 years ago
7 0
<span>If the force is fn, then it acting on the block, in the term of f2 and the other variables of the problems. then we assume the surface is rest on it's rigid, then the magnitude of the force is, fn =f2 sin(?) +m g</span>
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How to use Da Vinci flying pedulum clock
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3 years ago
A 14-gauge copper wire of diameter 1.628 mm carries a current of 12.5 What is the potential difference across a 2.00 - m length
Dvinal [7]

Answer:

V=1.76\times 10^{-4}\ V

Explanation:

Given that,

The diameter of a wire, d = 1.628 mm

Radius, r = 0.814  mm = 0.000814m

Current, I = 12.5 mA

The length of the wire, l = 2m

The resistivity of the wire, \rho=1.47\times 10^{-8}\ \Omega-m

We need to find the potential difference across the wire. We know that the resistance of the wire is given by :

R=\rho\dfrac{l}{A}

Also, V = IR

\dfrac{V}{I}=\rho\dfrac{l}{A}\\\\V=\dfrac{\rho l I}{A}\\\\V=\dfrac{1.47\times 10^{-8}\times 2\times 12.5\times 10^{-3}}{\pi \times (0.000814)^2}\\\\V=1.76\times 10^{-4}\ V

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3 years ago
The magnetic coils of a tokamak fusion reactor are in the shape of a toroid having an inner radius of 0.700 m and an outer radiu
iragen [17]

Answer:

(a) 11.3 T

(b) 6.09 T

Explanation:

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number of turns, N = 900

inner radius, r = 0.7 m

outer radius, R = 1.3 m

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B = \frac{\mu o}{4\pi}\times \frac{2 N\pi I}{R}

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(b) The magnetic field due to the outer radius is

B = 10^{-7}\times \frac{2\times 900\times 3.14\times 14000}{1.3}\\\\B = 6.09 T

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3 years ago
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