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Elena-2011 [213]
3 years ago
15

5 The frequencies of AM radio waves,

Physics
1 answer:
aleksklad [387]3 years ago
5 0
Message me back and I can help you.
You might be interested in
An object of mass 3 kg, moving with and sticks to an object of mass 2.00 kg with an initial velocity of 3.00 m/s. Find the final
Aleonysh [2.5K]

Answer:

1.8 m/s

Explanation:

momentum = mass × velocity

initial momentum = m1v1+m2v2

                             = 3×3 +2×0 = 9+0= 9 kg m/s

let combined velocity be V

HENCE  

final momentum = total mass × velocity

                            = (3+2) × V = 5V

According to law of conservation of momentum

final momentum = initial momentum

5V = 9

V =9/5

V = 1.8 m/s

8 0
3 years ago
Please help me answer this​
ivann1987 [24]

Answer:

A is the correct answer

Hope it helps

4 0
3 years ago
A forklift raises a 72-kg crate onto a shelf 3.6 meters above the floor. How much gravitational potential energy does the crate
Mademuasel [1]

Answer:

<h2>2540.16 J</h2>

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 72 × 9.8 × 3.6 = 2540.16

We have the final answer as

<h3>2540.16 J</h3>

Hope this helps you

8 0
3 years ago
The planets eccentricity in order least to greatest​
ankoles [38]

Answer:

Orbital Eccentricity

Planet Orbital Eccentricity

(Point in Orbit Closest to Sun)

measured in AU's

Mercury 0.206

Venus 0.007

Earth 0.017

Mars 0.093

Jupiter 0.048

Saturn 0.056

Uranus 0.047

Neptune 0.009

Pluto 0.248

Explanation:

link to information:

https://www.enchantedlearning.com/subjects/astronomy/glossary/Eccentricity.shtml

3 0
2 years ago
A high-performance sports car can go from 0 to 100 mph in 5.8 s. (Assume the car travels in the positive direction. Indicate the
sasho [114]

Answer: a) 7.71 m/s², b) - 6.67 m/s²

Explanation: first thing to note is that

1 mile = 1609.34

1 hour = 3600s

Hence, 100mph to m/s = (100 × 1609.34)/3600 = 44.71 m/s

Initial velocity (u) = 0, final velocity (v) = 44.71 m/s, t = 5.8s, a = acceleration =?

By using newton's laws of motion

v = u + at

44.71 = 0 + a(5.8)

44.71 = 5.8a

a = 44.71/5.8

a = 7.71 m/s²

Question b)

The car is completing a stop which implies that the car is coming to rest, and when a car is coming to rest, the final velocity (v) is zero.

Hence u = 34 m/s, v = 0, a =?, t = 5.1 s

v = u + at

0 = 34 + a(5.1)

a(5.1) = - 34

a = - 34/5.1

a = - 6.67 m/s².

The negative sign beside the acceleration shows that the body is decelerating

7 0
3 years ago
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