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ankoles [38]
2 years ago
11

(I NEED THIS ANSWERED NOW PLEASE)

Physics
1 answer:
VMariaS [17]2 years ago
4 0

Answer:

Zeros that follow non-zero numbers and are also to the right of a decimal point are significant.

Explanation:

For example:

0.300 has 3 significant figures.

5.400 has 4 significant figures.

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The term used to describe the quantity of matter that a body possesses is:
barxatty [35]
The term used to describe the quantity of matter that a body possesses is mass.
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3 years ago
A block of mass 1.5 hangs at the of end of a weight cord suspended from the ceiling.what is the tension in the cord, and with wh
Len [333]

The tension in the cord is 14.7 N and the force of pull of the cord is 14.7 N, assuming the block is stationary.

<h3>What is the tension in the cord?</h3>

The tension in the cord is calculated as follows;

T = ma + mg

where;

  • a is the acceleration of the block
  • g is acceleration due to gravity
  • m is mass of the block

T = m(a + g)

T = 1.5(a + 9.8)

T = 1.5a + 14.7

Thus, the tension in the cord is (1.5a + 14.7) N.

If the block is at rest, the tension is 14.7 N.

<h3>Force of the force</h3>

The force with which the cord pulls is equal to the tension in the cord

F = T = m(a + g)

F = (1.5a + 14.7) N

If the block is stationary, a = 0, the tension and force of pull of the cord = 14.7 N.

Thus, the tension in the cord is 14.7 N and the force of pull of the cord is 14.7 N, assuming the block is stationary.

Learn more about tension here: brainly.com/question/187404

#SPJ1

4 0
11 months ago
2. What will be the extension of this spring if the load is a) 4N and b) 75 g?
Furkat [3]

Answer:

6

Explanation:

just add

7 0
3 years ago
What occurs when a swimmer pushes through water to swim
Triss [41]
When we swim we apply force and push the water backward with the help of our hands. In response, The water pushes us forward with an equal force. Thus, in order to move forward and swim, the swimmer lushes the water backward. Newton's 3rd law of motion
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3 years ago
How long does it take a wheel that is rotating at 33.3 rpm to speed up to 78.0 rpm if it has an angular acceleration of 2.15 rad
Rzqust [24]

initial angular speed is given by 33.3 rpm

w_0 = 2\pi \frac{33.3}{60}

w_0 = 3.49 rad/s

final angular speed is given by 78 rpm

w_f = 2\pi \frac{78}{60}

w_f = 8.17 rad/s

now by using kinematics we will have

w_f = w_0 + \alpha * t

8.17 = 3.49 + 2.15 * t

t = 2.17 seconds

7 0
3 years ago
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