Sound from a source vibrating at frequency 200 Hz travels at the speed of 300 m/s in air.Wavelength of the sound is (in m/s)

What will be the value of both charges if they are 5 cm apart and suffer a

Mrac [35]

Answer:

$\boxed{q = 1.2 \times {10}^{ - 6} C}$

Explanation:

$f_e = \frac{{q}^{2}k }{ {r}^{2} } \\ q = \sqrt{ \frac{f_e( {r}^{2} )}{k} } = \sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } \\ q =\sqrt{ \frac{5.2(5 \times {10}^{ - 2} )^{2} }{9 \times {10}^{9} } } = \sqrt{ \frac{0.013}{9 \times {10}^{9} } } \\ q = 1.2 \times {10}^{ - 6}$

3 0

2 years ago

A force is applied to an object at rest with a mass of 100 kg. A force twice as large is applied to another object at rest with

MAVERICK [17]

The second object, the one that had twice the force applied to it, would move twice as far, I believe.

3 0

2 years ago

A plant worker accidentally breathes some stored gaseous tritium, a beta emitter with maximum particle energy of 0.0186 MeV. The

andrey2020 [161]

Answer:

400 milli-rems

Solution:

As per the question;

Maximum energy of particle, $E_{m} = 0.0186\ MeV$

Weight, w = 1 kg

Energy absorbed, E = $4\times 10^{- 3}\ J$

Now,

Equivalent dose is given by:

$D_{eq} = \frac{E}{w} =\frac{4\times 10^{- 3}}{1} = 4\times 10^{- 3}\ J/kg$

1 Gy = 1 J/kg

Also,

1 Gy = $1\times 10^{5}\ milli-rems$

Therefore,

Dose equivalent in milli-rems is given by:

$D_{eq} = 4\times 10^{- 3}\times 1\times 10^{5} = 400\ milli-rems$

8 0

3 years ago

Two golfers each hit a ball at the same speed, but one at 60 degrees with the horizontal and the other 30 degrees. a. Which ball

likoan [24]

Answer:

Therefore, both balls will hit the ground at the same distance from their respective starting points and at the same time.

Explanation:

Both balls will hit the ground at the same distance and at the same time assuming they both start at the same initial elevation from the ground.

We know that range in the projectile motion given as

$R=\dfrac{v_o^2sin2\theta}{g}$

sin 60° = sin 120° =0.866

Therefore, the maximum range will be identical assuming both golfers hit the ball at the same elevation from the ground.

As for the time...

Where v is 0 m/s (final velocity at highest point), v0 is the initial velocity (for both golfers) and is the acceleration due to gravity (-9.8 m/s^²). As you can see, the time it takes to get to the highest point is independent of the angle; it is only dependent on the initial velocity. Since both golfers hit the ball with the same speed, the time for the ball to reach the highest point will be the same. Also, since it's a parabola, you can multiply the time by 2 for each golfer to get the time it takes to hit the ground.

Therefore, both balls will hit the ground at the same distance from their respective starting points and at the same time.

5 0

3 years ago

50 points if you help me

satela [25.4K]

Answer:

X-precipitation

Y(plants)-photosynthesis

Y(animals)-respiration

W-evaporation

Explanation:

8 0

2 years ago