Answer:
maximum amplitude = 0.08 m
Explanation:
Given that
Time period T= 0.58 s
acceleration of gravity g= 9.8 m/s²
We know that time period of simple harmonic motion given as
T = 2π/ω
0.58 = 2π/ω
ω = 10.83rad/s
ω=angular frequency
Lets take amplitude = A
The maximum acceleration given as
a= ω² A
The maximum acceleration should be equal to g ,then block does not separate
a= ω² A
9.8 = 10.83² A
A = 0.08m
maximum amplitude = 0.08 m
1. is "A"
2. is "A"
3. is "B"
4. is "D"
Answer:
The magnetic force on a current-carrying wire is perpendicular to both the wire and the magnetic field with direction given by the right hand rule.
Answer:
The magnitude of the magnetic field at the origin is .
Explanation:
Given :
50-A wire is in the x-z plane and is 5 m from the z axis.
Also , 40-A wire is in the y-z plane and is 4 m from the z axis.
Now , since both the wire are perpendicular to each other .
Therefore , magnetic field are also perpendicular to each other .
Magnetic field at origin due to wire 1 is :
Magnetic field at origin due to wire 2 is :
Now , therefore net magnetic field is :
Putting value of
We get ,
Therefore, the magnitude of the magnetic field at the origin is .