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3 years ago

Why might an electromagnet be used to pick up old cars in junkyards?

Physics

2 answers:

siniylev [52]3 years ago

7 0

B) Hope it helps ,Have a nice day :)

Law Incorporation [45]3 years ago

6 0

<h3><u>Answer;</u></h3>

B) Electromagnets are powerful and can be turned on and off easily.

<h3><u>Explanation;</u></h3>

<em><u>Electromagnets are made by winding a wire through a magnetic material such as soft iron core making a coil, and then passing electric current through the coil thus making the soft iron core magnetic.</u></em>

The strength of the electromagnet depends on the number of coils and also the size of the electric current through the coil.

<em><u>Its advantageous to use electromagnets as compared to using permanent magnets since they are powerful and can be turned on and off easily and also the strength of the electromagnet can be easily adjusted by regulating the amount of current flowing through the coils. </u></em>

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Explanation:

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4vir4ik [10]

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3 years ago

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A modern compact fluorescent lamp contains 1.4 mg of mercury (Hg). If each mercury atom in the lamp were to emit a single photon

Reika [66]

Answer:

A. 1.64 J

Explanation:

First of all, we need to find how many moles correspond to 1.4 mg of mercury. We have:

$n=\frac{m}{M_m}$

where

n is the number of moles

m = 1.4 mg = 0.0014 g is the mass of mercury

Mm = 200.6 g/mol is the molar mass of mercury

Substituting, we find

$n=\frac{0.0014 g}{200.6 g/mol}=7.0\cdot 10^{-6} mol$

Now we have to find the number of atoms contained in this sample of mercury, which is given by:

$N=n N_A$

where

n is the number of moles

$N_A=6.022\cdot 10^{23} mol^{-1}$ is the Avogadro number

Substituting,

$N=(7.0\cdot 10^{-6} mol)(6.022\cdot 10^{23} mol^{-1})=4.22\cdot 10^{18}$ atoms

The energy emitted by each atom (the energy of one photon) is

$E_1 = \frac{hc}{\lambda}$

where

h is the Planck constant

c is the speed of light

$\lambda=508 nm=5.08\cdot 10^{-7}nm$ is the wavelength

Substituting,

$E_1 = \frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{5.08\cdot 10^{-7} m}=3.92\cdot 10^{-19} J$

And so, the total energy emitted by the sample is

$E=nE_1 = (4.22\cdot 10^{18} )(3.92\cdot 10^{-19}J)=1.64 J$

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3 years ago

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Lady bird [3.3K]

I have all the answers here so take this

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2 years ago

How is the pressure of a gas related to its concentration of particles?A) Pressure will expand a gas, enlarging its volume and r

Lesechka [4]

Answer:

C) Pressure will compress a gas, reducing its volume and giving it a greater density and concentration of particles.

Explanation:

At constant temperature, pressure and volume are inversely related.

P V = constant

$\Rightarrow P \propto \frac{1}{V}$

As the pressure increases, the gas compresses, the particles come closer reducing the volume of gas.

As we know, with decrease in volume, density increases.

$Density = \frac{Mass}{Volume}$

$Density \propto \frac{1}{Volume}$

Thus, the pressure of a gas is directly related to concentration of particles. Increase in pressure causes increase in concentration of the particles.

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3 years ago