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3 years ago

The pressure of air pushing down on a house roof is extremely large. Why is the roof not crushed?

1 answer:

7 0

There is still air inside of a house, which is pushing the roof upwards, so the forces are equal and the roof is not crushed.

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Consider shining a laser through a small circular hole. The resulting diffraction pattern will look like a bullseye - a series o

jeka57 [31]

Hey, good morning. I hope u have a wonderful day doing ur work :)

6 0

2 years ago

What do we call the distance between any two successive crests of a wave

icang [17]

That is actually called the Wave Length.

8 0

2 years ago

1) Consider an electric power transmission line that carries a constant electric current of i = 500 A. The cylindrical copper ca

JulsSmile [24]

Answer:

t = 1.27 x 10⁹ s

Explanation:

First, we will find the volume of the wire:

Volume = V = AL

where,

A = Cross-sectional area of wire = πr² = π(1 cm)² = π(0.01 m)² = 3.14 x 10⁻⁴ m²

L = Length of wire = 150 km = 150000 m

Therefore,

V = 47.12 m³

Now, we will find the number of electrons in the wire:

No. of electrons = n = (Electrons per unit Volume)(V)

n = (8.43 x 10²⁸ electrons/m³)(47.12 m³)

n = 3.97 x 10³⁰ electrons

Now, we will use the formula of current to find out the time taken by each electron to cross the wire:

$I =\frac{q}{t}$

where,

t = time = ?

I = current = 500 A

q = total charge = (n)(chareg on one electron)

q = (3.97 x 10³⁰ electrons)(1.6 x 10⁻¹⁹ C/electron)

q = 6.36 x 10¹¹ C

$500\ A = \frac{6.36\ x\ 10^{11}\ C}{t}\\\\t = \frac{6.36\ x\ 10^{11}\ C}{500\ A}$

Therefore,

7 0

2 years ago

A Gaussian surface in the form of a hemisphere of radius R = 3.04 cm lies in a uniform electric field of magnitude E = 1.64 N/C.

Likurg_2 [28]

Answer:

Part a)

$\phi = -4.76 \times 10^{-3} Nm^2/C$

Part b)

$\phi_{curved} = 4.76 \times 10^{-3} Nm^2/C$

Explanation:

Part a)

Electric flux entering into the base

so it is given as

$\phi = E.A$

$\phi = - EA$

$\phi = -(1.64)(\pi r^2)$

$\phi = -(1.64)(\pi\times 0.0304^2)$

$\phi = -4.76 \times 10^{-3} Nm^2/C$

Part b)

Now since we know that there is no enclosed charge in the hemisphere

so net flux must be zero

$\phi_{curved} + \phi_{flat} = 0$

$\phi_{curved} - 4.76 \times 10^{-3} = 0$

$\phi_{curved} = 4.76 \times 10^{-3} Nm^2/C$

7 0

2 years ago

A light spring has a force constant of 70 N/m and is used to pull a 10 kg box on a horizontal frictionless surface. If the box h

Sergio039 [100]

Answer:

82.4 cm

Explanation:

∑F = ma

kx cos θ = ma

x = ma / (k cos θ)

x = (10 kg) (5 m/s²) / (70 N/m cos 30.0°)

x = 0.824 m

x = 82.4 cm

8 0

2 years ago