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slamgirl [31]
3 years ago
10

How much of 500 grams of carbon-14 remains after 28,575 years?

Chemistry
1 answer:
ser-zykov [4K]3 years ago
7 0

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Calculate how many grams of o2(g) can be produced from heating 87.4 grams of kclo3(s).
Rufina [12.5K]
<span>34.2 grams Lookup the atomic weights of the involved elements Atomic weight potassium = 39.0983 Atomic weight Chlorine = 35.453 Atomic weight Oxygen = 15.999 Molar mass KClO3 = 39.0983 + 35.453 + 3 * 15.999 = 122.5483 g/mol Moles KClO3 = 87.4 g / 122.5483 g/mol = 0.713188188 mol The balanced equation for heating KClO3 is 2 KClO3 = 2 KCl + 3 O2 So 2 moles of KClO3 will break down into 3 moles of oxygen molecules. 0.713188188 mol / 2 * 3 = 1.069782282 mols So we're going to get 1.069782282 moles of oxygen molecules. Since each molecule has 2 atoms, the mass will be 1.069782282 * 2 * 15.999 = 34.23089345 grams Rounding the results to 3 significant figures gives 34.2 grams</span>
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3 years ago
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miskamm [114]
The answer is either A or B I’m not sure
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The analogy that forms the basis of the octet rule compares covalent valence
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How many grams of hydrogen gas would be needed to form 8.0 grams of water? H2+O2=H2O
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