What substitution should be used to rewrite 16(x^3+1)^2-22(x^3+1)-3=0 as a quadratic equation?
2 answers:
You might be interested in
Step-by-step explanation:
y-2 = - 3(x-3)
y - 2 =-3x +9
y -2 +2 = - 3x +9 +2
y = - 3x +11
To find the the coordinate
When x =0
y = - 3(0) +11
y= 11
When y = 0
0 = - 3x +11
Subtract 11 from both sides
-3x = - 11
x = 11/3
The y intercept is 11 so, one of your points will be at (0, 11) while the other will be at (11/3, 11).
