All categories

1 year ago

What is the hydroxide ion concentration of a solution with a ph of 8. 25?

Chemistry

1 answer:

miss Akunina [59]1 year ago

5 0

The concentration of hydroxide ion of a solution with a pH of 8. 25 is 1.77× $10^{6}$ M

Calculation,

The pH of a solution tells us about concentration of the $H^{+$ ion ( proton ) in solution. However, if we know the value of pH , we can calculate pOH with the help of pH and from pOH we can find concentration of hydroxide ions in the solution.

pH + pOH = 14

8. 25 + pOH = 14

pOH = 14 - 8. 25 = 5.75

Since, pH = -㏒[ $H^{+$ ]

Similarly, pOH = -㏒[ $OH^{-$ ]

If pOH = 5.75 , that means that -㏒[ $OH^{-$ ] = 5.75 ,which means that,

[ $OH^{-$ ] = $10^{-5.75}$ = 1.77× $10^{6}$ .

So, we know that the concentration of the $OH^{-$ ions in the solution with pH of 8.25 is 1.77× $10^{6}$ Molar

to learn more about hydroxide ion

brainly.com/question/25883474

#SPJ4

You might be interested in

12 Describe In your own words, describe the glassblowing process.

Vikentia [17]

Explanation:

To give the glass its final shape and size, it is blown into with a blowpipe, creating a sort of bubble of glass. To carry out this process, the blowpipe holding the glass must be placed on a steel stand. Then, the glass artist has to blow into the blowpipe while rotating it at the same

4 0

2 years ago

Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm

8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

$\frac{dV}{dt}=10\frac{cm^3}{s}$

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

$\frac{dh}{dt} = ?*\frac{dV}{dt}$

Of course, $?=\frac{dh}{dV}$ .

Now, since the volume of a cone is $V=\pi r^2h/3$ and the ratio $r/h=15/20=3/4$ or $r=3/4h$ , the volume becomes:

$V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3$

We proceed to its differentiation:

$\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}$

Then, we compute $\frac{dh}{dt}$

$\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}$

Finally, at h=2:

$\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}$

Best regards.

4 0

3 years ago

Please help! Don’t know if I’m right!!

kompoz [17]

Answer:e

Explanation:

Bananas

4 0

3 years ago

Which member of each pair is more soluble in diethyl ether? Why?<br> (c) MgBr₂(s) or CH₃CH₂MgBr(s)

White raven [17]

CH3CH2MgBr is more soluble in diethyl ether .

We know that polar solvent dissolve in polar solvent very perfectly . as diethyl ether is a polar solvent so it have dipole -dipole interaction .

Hence the compound with similar interaction can dissolve in diethyl ether .

Here , MgBr2 is an ionic compound . there is ion-ion interactions occurs which is not similar to dipole -dipole interaction in diethyl ether .hence the solubility of MgBr2 in diethyl ether is less .

but in case of CH3CH2MgBr there are both polar and nonpolar end .CH3CH2 is the nonpolar end and MgBr is the polar end .

thus with the nonpolar end solute interact using depression forces and with polar end solute interact using dipole-dipole interaction . so CH3CH2MgBr is more soluble .

Learn more about polar solvent here :

brainly.com/question/3184550

#SPJ4

4 0

2 years ago

Need help with the balancing one

DochEvi [55]

The third option, 2,2,1,2

8 0

3 years ago