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Feliz [49]
1 year ago
11

What is the hydroxide ion concentration of a solution with a ph of 8. 25?

Chemistry
1 answer:
miss Akunina [59]1 year ago
5 0

The concentration of hydroxide ion of a solution with a pH of 8. 25 is 1.77×10^{6} M

Calculation,

The pH of a solution tells us about concentration of the H^{+ ion ( proton ) in solution. However, if we know the value of pH , we can calculate pOH with the help of pH and from pOH we can find concentration of hydroxide ions in the solution.

pH + pOH = 14

8. 25 + pOH = 14

pOH = 14 - 8. 25 = 5.75

Since, pH = -㏒[ H^{+ ]

Similarly, pOH = -㏒[OH^{- ]

If pOH = 5.75 , that means that -㏒[OH^{- ]  = 5.75 ,which means that,

[OH^{- ]  = 10^{-5.75} = 1.77×10^{6}.

So, we know that the concentration of the OH^{- ions in the solution with pH of 8.25 is 1.77×10^{6} Molar

to learn more about hydroxide ion

brainly.com/question/25883474

#SPJ4

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Sports drinks contain sugar, salt, and flavorings dissolved in water . They can be made more or less sweet by adding different a
givi [52]

Answer:

It's a mixture.

Explanation:

Answer from Edgenuity

8 0
3 years ago
Which of the following are weak electrolytes in aqueous solutions? Select ALL that apply.
Mandarinka [93]

Answer:

Weak electrolytes are

HgCl2 and NH₃

Explanation:

  • Electrolytes are compounds that conduct electricity while in molten or aqueous form.
  • Electrolytes may therefore be decomposed by passing electric current through them.
  • They may be either strong or weak electrolytes.
  • Strong electrolytes are those that ionize completely to form mobile ions while weak electrolytes ionize partially to generate ions.
  • Examples of weak electrolytes  are HgCl2, NH₃
  • Examples of strong electrolytes are LiOH, HClO₄, and HI.

3 0
3 years ago
Phosphorus-32 (32P) is an isotope that is commonly used for medical and biological research. Phosphorus-32 has a half-life of 14
Pachacha [2.7K]

The activity of the sample when it was shipped from the manufacturer is 4.54 mCi

<h3>How to determine the number of half-lives that has elapsed </h3>

From the question given above, the following data were obtained:

  • Time (t) = 48 hours
  • Half-life (t½) = 14.28 days = 14.28 × 24 = 342.72 hours
  • Number of half-lives (n) =?

n = t / t½

n = 48 / 342.72

n = 0.14

<h3>How to determine the activity of the sample during shipping </h3>
  • Number of half-lives (n) = 0.14
  • Original activity (N₀) = 5.0 mCi
  • Activity remaining (N) =?

N = N₀ / 2ⁿ

N = 5 / 2^0.14

N = 4.54 mCi

Thus, the activity of the sample during shipping is 4.54 mCi

Learn more about half life:

brainly.com/question/2674699

5 0
2 years ago
Transition metals can be found in Families 3 through 12 on the periodic table. What property do transition metals share?
Vedmedyk [2.9K]
The answer might be C
8 0
3 years ago
Read 2 more answers
What is the mass of the solid NH4Cl formed when 75.5 g of NH3 is mixed with an equal mass of HCl? What is the volume of the gas
Gekata [30.6K]

Answer : The volume of the gas remaining is 56.5 liters.

The gas is hydrochloric acid and the formula of the gas is HCl.

The mass of NH_4Cl produced is, 110.7 grams.

Explanation :

The balanced chemical reaction will be:

NH_3+HCl\rightarrow NH_4Cl

First we have to calculate the moles of NH_3 and HCl

\text{Moles of }NH_3=\frac{\text{Mass of }NH_3}{\text{Molar mass of }NH_3}

Molar mass of NH_3 = 17 g/mole

\text{Moles of }NH_3=\frac{75.5g}{17g/mole}=4.44mole

and,

\text{Moles of }HCl=\frac{\text{Mass of }HCl}{\text{Molar mass of }HCl}

Molar mass of HCl = 36.5 g/mole

\text{Moles of }HCl=\frac{75.5g}{36.5g/mole}=2.07mole

Now we have to calculate the limiting and excess reagent.

From the balanced reaction we conclude that

As, 1 mole of HCl react with 1 mole of NH_3

So, 2.07 mole of HCl react with 2.07 mole of NH_3

From this we conclude that, NH_3 is an excess reagent because the given moles are greater than the required moles and HCl is a limiting reagent and it limits the formation of product.

The remaining moles of HCl gas = 4.44 - 2.07 = 2.37 moles

Now we have to calculate the volume of the gas remaining.

Using ideal gas equation :

PV = nRT

where,

P = Pressure of gas = 752 mmHg = 0.989 atm     (1 atm = 760 mmHg)

V = Volume of gas = ?

n = number of moles of gas = 2.37 moles

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 14.0^oC=273+14.0=287K

Putting values in above equation, we get:

0.989atm\times V=2.37mole\times (0.0821L.atm/mol.K)\times 287K

V = 56.5 L

Now we have to calculate the moles of NH_4Cl

As, 1 mole of HCl react with 1 mole of NH_4Cl

So, 2.07 mole of HCl react with 2.07 mole of NH_4Cl

Now we have to calculate the mass of NH_4Cl

\text{ Mass of }NH_4Cl=\text{ Moles of }NH_4Cl\times \text{ Molar mass of }NH_4Cl

Molar mass of NH_4Cl = 53.5 g/mole

\text{ Mass of }NH_4Cl=(2.07moles)\times (53.5g/mole)=110.7g

Thus, the volume of the gas remaining is 56.5 liters.

The gas is hydrochloric acid and the formula of the gas is HCl.

The mass of NH_4Cl produced is, 110.7 grams.

3 0
3 years ago
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