I think the correct answer from the choices listed above is option D. When a molecular compound melts, they undergo the process of phase change from solid to liquid therefore m<span>olecules arranged in a regular pattern change to an irregular pattern. Hope this answers the question.</span>
Answer:
There isn't any picture for me to see
have a good day :)
Explanation:
A because that honestly just makes the most sense
The oxidation state of Chromium chloride (III) is +3
How can we find the answer?
First of all write down what you know about the molecule:
1: The molecule hasn't got an electric charge (is not an ione), this means that either positive and negative charges of its atoms are balanced (we have the same number of positve and negative charges)
2: Since it's a salt, where the metal is chromium and the non metal is the alogen Chlorine, we know that the negative charge belogns to the non metal element because of its elettronegativity, therefore the positive charge belongs to the metale element (chromium).
3: when chlorin forms binary salts its oxidation state is always -1 (you can find out this info in a periodic table)
In <span>CrC<span>l3</span></span> we have 3 chlorine atoms where each of them carrys 1 negative charge, so the total amount of negative charges is -3
Since the charges are balanced, the question is: Which is the positive charge that Chromium must carry in order to balance 3 negative charges?
The answer comes out to +3
Answer:
43.75 g of Nitrogen
Explanation:
We'll begin by calculating the mass of 1 mole of NH₄NO₃. This can be obtained as follow:
Mole of NH₄NO₃ = 1 mole
Molar mass of NH₄NO₃ = 14 + (4×1) + 14 + (3×16)
= 14 + 4 + 14 + 48
= 80 g/mol
Mass of NH₄NO₃ =?
Mass = mole × molar mass
Mass of NH₄NO₃ = 1 × 80 = 80 g
Next, we shall determine the mass of N in 1 mole of NH₄NO₃.
Mass of N in NH₄NO₃ = 2N
= 2 × 14
= 28 g
Thus,
80 g of NH₄NO₃ contains 28 g of N.
Finally, we shall determine the mass of N in 125 g of NH₄NO₃. This can be obtained as follow:
80 g of NH₄NO₃ contains 28 g of N.
Therefore, 125 g of NH₄NO₃ will contain = (125 × 28) / 80 = 43.75 g of N.
Thus, 125 g of NH₄NO₃ contains 43.75 g of Nitrogen
