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Korolek [52]
3 years ago
15

Put the steps in order to produce the output shown below. Assume the indenting will be correct in the program.

Computers and Technology
1 answer:
PolarNik [594]3 years ago
4 0

Code:

for numE in [2, 6]:

   for numF in [3, 5]:

      print(numE, numF)

Explanation:

Since the first number of the first output is 2, the outer loop must contain the list [2, 6], meaning 'for numE in [2, 6]:' is on line 1. This leaves us with 'for numF in list [3, 5]:' as the nested loop (line 2), and the print statement on line 3 since it needs to print both numE and numF.

Hope this helps :)

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Answer:

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c)

customerRecord.firstName

d)

customerPtr->firstName or (*customerPtr).firstName

e)

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f)

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g)

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3 years ago
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