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Korolek [52]
3 years ago
15

Put the steps in order to produce the output shown below. Assume the indenting will be correct in the program.

Computers and Technology
1 answer:
PolarNik [594]3 years ago
4 0

Code:

for numE in [2, 6]:

   for numF in [3, 5]:

      print(numE, numF)

Explanation:

Since the first number of the first output is 2, the outer loop must contain the list [2, 6], meaning 'for numE in [2, 6]:' is on line 1. This leaves us with 'for numF in list [3, 5]:' as the nested loop (line 2), and the print statement on line 3 since it needs to print both numE and numF.

Hope this helps :)

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1) Open the file DiceSimulation.java attached below. Create a new project on NetBeans called DiceSimulation. Copy the code from
trapecia [35]

Answer:

As per regulations, I can only answer the code in while loop.

Explanation:

Code in JAVA is given below for while loop

Please read all the comments for better understanding of the code.

Every step is explained well in the code.

Note class name is DiceSimulation.

Code in JAVA (Using while loop)::

import java.util.Random; // Needed for the Random class

/**

This class simulates rolling a pair of dice 10,000 times and counts the number of times doubles of are rolled for each different pair of doubles.

*/

public class DiceSimulation

{

public static void main(String[] args)

{

final int NUMBER = 10000; // Number of dice rolls

// A random number generator used in

// simulating the rolling of dice Random generator = new Random();

int die1Value; // Value of the first die

int die2Value; // Value of the second die

int count = 0; // Total number of dice rolls

int snakeEyes = 0; // Number of snake eyes rolls

int twos = 0; // Number of double two rolls

int threes = 0; // Number of double three rolls

int fours = 0; // Number of double four rolls

int fives = 0; // Number of double five rolls

int sixes = 0; // Number of double six rolls

// TASK #1 Enter your code for the algorithm here

/**

* Following while loop will run until count < Number.

*/

while(count<NUMBER){

/**

* To generate random number in range 1 to 6,

* I have declared two integer variables named min and max

* and initialized to 1 and 6 respectively.

*/

int min=1,max=6;

/**

* An object of Random class named rand is created so that we can generate

* random number.

*/

Random rand=new Random();

 

/**

* Using following formula we get random number in range 1 to 6.

* Both variables i.e die1Value and die2Value are initialized

* with the formula given in each iteration.

*/

die1Value = rand.nextInt((max - min) + 1) + min;

die2Value = rand.nextInt((max - min) + 1) + min;

 

/**

* Now we are interested in cases where there is double i.e

* Both random generated numbers in die1Value and die2Value are same.

*/

if(die1Value==die2Value){

/**

* Now there are 6 possibilities. They are shown in Nested IF-ELSE-IF statements.

* As both values are same, I have taken die1Value to check if it is 1,2,3,4,5 or 6.

*/

if(die1Value==1){

/**

* If die1Value is 1 then we increment snakeEyes by 1.

* Similarly for others too we do the same.

*/

snakeEyes++;

}else if(die1Value==2){

twos++;

}else if(die1Value==3){

threes++;

}else if(die1Value==4){

fours++;

}else if(die1Value==5){

fives++;

}else if(die1Value==6){

sixes++;

}

}

/**

* In each iteration we increment count by 1.

*/

count++;

}//While loop ends here.

// Display the results

System.out.println ("You rolled snake eyes " + snakeEyes + " out of " + count + " rolls.");

System.out.println ("You rolled double twos " + twos + " out of " + count + " rolls.");

System.out.println ("You rolled double threes " + threes + " out of " + count + " rolls.");

System.out.println ("You rolled double fours " + fours + " out of " + count + " rolls.");

System.out.println ("You rolled double fives " + fives + " out of " + count + " rolls.");

System.out.println ("You rolled double sixes " + sixes + " out of " + count + " rolls.");

 

}//main ends

}//class ends

4 0
3 years ago
What job titles describes a person with green engery? in career clusters
Amiraneli [1.4K]

Answer:

environmental scientist

Explanation:

8 0
3 years ago
You are a solutions engineer working for a large communications company that is migrating its existing server estate to AWS. You
erik [133]

Answer:

4 subnets

Explanation:

According to the specifications provided, it seems that you would need a total of 4 subnets for the entire server structure. This is because each web server needs 1 public subnet and each database needs one private subnet. If there are a total of 2 web servers and 2 database servers then each one will ultimately have 2 subnets meaning a total of 4 subnets. These would be 2 public subnets and 2 private subnets for the different availability zones, which would allow the server structure to maintain high availability.

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3 years ago
A university wants to schedule the classrooms for final exams. The attributes are given below:
iVinArrow [24]

Answer:

See explaination

Explanation:

Clearly the entities are as follows:-

Course

Section

Room

Test

The relationship among entities are as follows:-

Course has Section

Test is conducted for Course

Test is conducted in Section

Test is conducted in Room

Attributes of each entities are as follows:-

Course (CourseID, Name, Department)

Section (SectionID, Enrollment)

Room (RoomNumber, Capacity, Building)

Test (Time)

Section is a week entity as, there may be same sections for different courses, therefore section uses the primary key of course entity as foreign key.

Also entity Test is dependent upon the entities Room,Section and Course, therefore primary keys of these entities will be used as foreign key in the Test entity.

Check attachment for the ER diagram

5 0
3 years ago
In numerical methods, one source of error occurs when we use an approximation for a mathematical expression that would otherwise
Shtirlitz [24]

Answer:

The function in Python is as follows:

import math

import numpy as np    

def exp(x):

   mylist = []

   for n in range(10):

       num = (x**n)/(math.factorial(n))

       mylist.append([num])

   exp_approx = np.asarray(mylist)

   sum = 0

   for num in exp_approx:

       sum+=num

   return sum

Explanation:

The imports the python math module

import math

The imports the python numpy module

import numpy as np    

The function begins here

def exp(x):

This creates an empty list

   mylist = []

This iterates from 0 to 9

   for n in range(10):

This calculates each term of the series

       num = (x**n)/(math.factorial(n))

This appends the term to list, mylist

       mylist.append([num])

This appends all elements of mylist to numpy array, exp_approx

   exp_approx = np.asarray(mylist)

This initializes the sum of the series to 0

   sum = 0

This iterates through exp_approx

   for num in exp_approx:

This adds all terms of the series

       sum+=num

This returns the calculated sum

   return sum

3 0
3 years ago
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