Answer:
I think the answers are input, processes, output
Answer:
Java Class given below
Explanation:
class ReadOnly
{
protected int val;
public ReadOnly(int arg)
{
val = arg;
}
public int getVal()
{
return val;
}
}
class ReadWrite extends ReadOnly
{
private boolean dirty;
public ReadWrite(int arg)
{
super(arg);
dirty = false;
}
public void setVal(int arg)
{
val = arg;
dirty = true;
}
public boolean isDirty()
{
return dirty;
}
}
Explanation:
Online Movie Ticket Booking System is a website to provide the customers facility to book tickets for a movie online and to gather information about the movies and theaters. Customer needs to register at the site to book tickets to the movie
Advantages of Online Booking Systems
Your business is open around the clock. ...
You can maximize reservations. ...
You get paid quicker. ...
You're not tied to a phone. ...
You can effortlessly up-sell add-ons. ...
It's easy to manage your calendar. ...
You get valuable insight about your business
Complete Question:
A campus bookstore sells both types and in the last semester sold 56% laptops and 44% desktops. Reliability rates for the two types of machines are quite different, however. In the first year, 5% of desktops require service, while 15% of laptops have problems requiring service.
Given that a computer required service, what is the probability that it was a laptop?
Answer:
Probability = 0.084
Explanation:
Given
Laptops = 56%
Desktop = 44%
Service Required (Laptop) = 15%
Service Required (Desktop) = 5%
Required
Determine the probability that a selected computer is a laptop and it requires service.
The question tests our knowledge of probabilities using "and" condition.
What the question requires is that, we calculate the probability of selecting a LAPTOP that REQUIRES SERVICE
Note the capitalised words.
This will be calculated as follows:
Probability = P(Laptop) and P(Service Required (Laptop))
[Substitute values for P(Laptop) and P(Service Required (Laptop))]
Probability = 56% * 15%
[Convert to decimal]
Probability = 0.56 * 0.15
Probability = 0.084
More than one contact can be added to the group at a time.
