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Murrr4er [49]
3 years ago
14

By what factor is the self-inductance of an air solenoid changed if its length and number of coil turns are both tripled

Physics
1 answer:
fredd [130]3 years ago
4 0

Answer:

The new self inductance is 3 times of the initial self inductance.

Explanation:

The self inductance of a solenoid is given by :

L=\dfrac{\mu_oN^2 A}{L}

Where

N is number of turns per unit length

A is area of cross section

l is length of solenoid

If length and number of coil turns are both tripled,

l' = 3l and N' = 3N

New self inductance is given by :

L'=\dfrac{\mu_oN'^2 A}{L'}\\\\=\dfrac{\mu_o(3N)^2 A}{3L}\\\\=3\dfrac{\mu_oN^2 A}{L}\\\\=3L

So, the new self inductance is 3 times of the initial self inductance.

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Answer:

a)

z=561.7

b)

z=214.1

Explanation:

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a)

f = frequency = 55.7 Hz

Impedance is given as

z=\frac{1}{2\pi fC} - 2\pi fL

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z=561.7

b)

f = frequency = 11000 Hz

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FrozenT [24]

Answer:

If you were traveling away from earth at speed 0.5c, you wouldn't notice any change in your heartbeat, you won't notice your mass, height and waistline change. This is because you are on the same frame of reference as the ship in spacetime and any measurement done from the ship will give normal readings from an observer on the ship.

For an observer on earth, your heartbeat will be seen to slowdown (because your time on the ship will be perceived to slow down to an

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physics a flower pot falls from a windowsill 25.0m above the sidewalk. how much time does a passerby on the sidewalk below have
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v_f^2 = v_0^2 + 2*a*d
Since the flower pot is dropped, it has an initial velocity of zero. Also the flower pot accelerates due to gravity.

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