At summer camp, the swimming course runs the length (L) of a small lake. To determine the length of the course, the camp counsel
1 answer:
<u>Answer:</u>
<em>The length of the swimming course is 47.16 meters.</em>
<u>Explanation:</u>
It is given that the right triangle overlaps the lake and hypotenuse L runs through the length of the lake. Thus length of the lake will be the length of this hypotenuse.
The instructors have conducted measurements of the right triangle and has found the legs to be 25 and 40 meters. The sum of squares of base and height of a right triangle gives the value of its hypotenuse according to Pythagoras theorem.
Thus
b - base
h - height.
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Power is defined as the rate at which the body is doing work:
Work is defined as displacement done by the force times that displacement:
We know that we need 62N to move the box, so when we apply this force along the path of 10m we have done:
of work.
Now we just divide that by 5s to get how much power is required:
Work is defined as displacement done by the force times that displacement:
We know that we need 62N to move the box, so when we apply this force along the path of 10m we have done:
of work.
Now we just divide that by 5s to get how much power is required:
Answer:
6.57 m/s
Explanation:
First use Hook's Law to determine the F the compressed spring acts on the mass. Hook's Law F=kx; F=force, k=stiffnes of spring (or spring constant), x=displacement
F=kx; F=180(.3) = 54 N
Next from Newton's second law find the acceleration of the mass.
Newton's .2nd law F=ma; a=F/m ; a=54/.75 = 72m/s²
Now use the kinematic equation for velocity (or speed)
v₂²= v₀² + 2a(x₂-x₀); v₂=final velocity; v₀=initial velocity; a=acceleration; x₂=final displacement; x₀=initial displacment.
v₀=0, since the mass is at rest before we release it
a=72 m/s² (from above)
x₀=0 as the start position already compressed
x₂=0.3m (this puts the spring back to it's natural length)
v₂²= 0 + 2(72)(0.3) = 43.2 m²/s²
v₂= = 6.57 m/s