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2 years ago

1. 1. are the charged parts of an atom.

Physics

2 answers:

victus00 [196]2 years ago

5 0

Answer:

» e. Electrons and protons

Explaination :

Electrons are negatively charged and protons are positively charged.

The neutrons do not have a charge.

wlad13 [49]2 years ago

4 0

Answer:

e. Electrons and protons

Explanation:

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What is physics and important of physics

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Physics is the answer to all the forces in nature and it is important to know all of that in a day to day life to succeed in life

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2 years ago

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Compressing the air by squeezing the bottle was accompanied by a(n) ________ in the temperature of air inside the bottle

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Increase in temprature

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2 years ago

Suppose a scientist conducts a series of experiments and the results are so amazing she wants to share them with other experts i

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The results have not been through the rigorous process of peer review

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When a scientist conducts a study and obtains results, those results ought to be submitted to a reputable journal where the results would go through the rigorous protocol of peer review.

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2 years ago

A boy pushes forward a cart of groceries with a total mass of 40.0 kg. What is the acceleration of the cart if the net force on

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3 years ago

Some hypothetical alloy is composed of 12.5 wt% of metal A and 87.5 wt% of metal B. If the densities of metals A and B are 4.27

densk [106]

Answer:

The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

Explanation:

Given that,

Weight of metal A = 12.5%

Weight of metal B = 87.5%

Length of unit cell = 0.395 nm

Density of A = 4.27 g/cm³

Density of B= 6.35 g/cm³

Weight of A = 61.4 g/mol

Weight of B = 125.7 g/mol

We need to calculate the density of the alloy

Using formula of density

$\rho=n\times\dfrac{m}{V_{c}\times N_{A}}$

$n=\dfrac{\rho\timesV_{c}\times N}{m}$ ....(I)

Where, n = number of atoms per unit cells

m = Mass of the alloy

V=Volume of the unit cell

N = Avogadro number

We calculate the density of alloy

$\rho=\dfrac{1}{\dfrac{12.5}{4.27}+\dfrac{87.5}{6.35}}\times100$

$\rho=5.98$

We calculate the mass of the alloy

$m=\dfrac{1}{\dfrac{12.5}{61.4}+\dfrac{87.5}{125.7}}\times100$

$m=111.15$

Put the value into the equation (I)

$n=\dfrac{5.9855\times(0.395\times10^{-9}\times10^{2})^3\times6.023\times10^{23}}{111.15}$

$n=1.99\approx 2\ atoms/cell$

Hence, The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

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3 years ago