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IRISSAK [1]
3 years ago
7

A spacecraft is launched from Earth toward the moon. Where will the spacecraft be when the gravitational forces acting on it are

equal? closer to Earth than to the moon because the moon has greater mass than Earth closer to the moon than to Earth because the moon has greater mass than Earth closer to Earth than to the moon because Earth has greater mass than the moon closer to the moon than to Earth because Earth has greater mass than the moon
Physics
1 answer:
Gnoma [55]3 years ago
5 0

Answer:b

Explanation:

Itwm

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The intensity ratio at point A and B will be 81:16.

<u>Explanation:</u>

Sound waves are known to get faded with increase in the distance. This is because, the intensity of the sound is inversely proportional to the square of the distance of the source from the observer. So, if an observer is standing greater distance from the source of the sound, he/she will find difficulty in hearing the sound.

So, as the distance between the source and observer increases, the intensity of the sound wave decreases.

I = \frac{1}{r^{2} }

As here two points A and B are located at 4 m and 9 m distance from the source, then the intensity of sound at A and B will be inversely proportional to their respective square of the distance as shown below.

I_{A} =\frac{1}{r_{A}^{2}  }  = \frac{1}{4 \times 4}=\frac{1}{16}

Similarly,

I_{B} =\frac{1}{r_{B}^{2}  }  = \frac{1}{9 \times 9}=\frac{1}{81}

So, the ratio of intensity at point A and B will be

\frac{I_{A} }{I_{B} } = \frac{81}{16} =81:16

Thus, the intensity ratio at point A and B will be 81:16.

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