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nasty-shy [4]
3 years ago
9

Amino acids are the building blocks of proteins. The simplest amino acid is glycine (H2NCH2COOH). Draw a Lewis structure for gly

cine. (Hint: The central atoms in the skeletal structure are nitrogen bonded to carbon, which is bonded to another carbon. The two oxygen atoms are bonded directly to the right-most carbon atom.) Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all hydrogen atoms and nonbonding electrons.
Chemistry
1 answer:
VashaNatasha [74]3 years ago
3 0

Answer:

Explanation:

The lewis structure (indicating all the atoms and patterns provided as hint in the question) of glycine can be seen in the attachment below. While the chemical structure of glycine can be seen below

         H

          |

H₂N - C - C =O

          |      \

         H      OH

The structure (of glycine) above provides a "fair idea" of how the lewis structure will be.

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SCORPION-xisa [38]

Answer:

Last one

Explanation:

5 0
3 years ago
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a major textile dye manufacutrer developed a new yellow dye. the dye has a percent composition of 75.95%C, 17.72%n and 6.33%H by
Delicious77 [7]

The molecular formula of dye:

A major textile dye manufacturer developed a new yellow dye with a molecular formula C_{15}N_{3}H_{15}.

Given:

Percentage composition:

C = 75.95%

N = 17.72%

H = 6.33%

Molar mass = 240 g

To find: molecular formula of dye

Calculation:

Let's assume the mass of the compound is 100 gm.

So,  Mass of C = 75.95 gm

Mass of N = 17.72 gm

Mass of H = 6.33 gm

The number of moles = given mass/mass

Therefore, the number of moles of C = 75.95/12 = 6.33

The number of moles of N = 17.72/14 = 1.27

Number of moles of H =6.33/1 = 6.33

Simplest ratio:

C = 6.33/1.27 = 4.98 =5

N = 1.27/1.27 = 1

H = 6.33/1.27 = 4.98 =5

Therefore, the empirical formula is C_{5}NH_{5}

The mass of empirical formula = 12 x 5 + 14 + 1 x 5 = 79 gm

Number of moles= molar mass/ empirical formula

n = 240/79 = 3.04 =3

Therefore, molecular formula = empirical formula x n

Hence, molecular formula = C_{15}N_{3}H_{15}

Learn more about molecular formulas here,

brainly.com/question/24083714

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6 0
2 years ago
Suppose 10.0 mL of 2.00 MNaOH is added to (a) 0.780 L of pure water and (b) 0.780 L of a buffer solution that is 0.682 Min butan
katrin2010 [14]

Answer:

a) pH will be 12.398

b) pH will be 4.82.

Explanation:

a) The moles of NaOH added = molarity X volume (L) = 2 X 0.01 = 0.02 moles

The total volume after addition of pure water = 0.780+0.01 = 0.79 L

The new concentration of /NaOH will be:

molarity=\frac{molesofsolute}{volumeofsolution}=\frac{0.02}{0.79}=0.025M

the [OH⁻] = 0.025

pOH = -log [OH⁻] = 1.602

pH = 14 -pOH = 12.398

b) The buffer has butanoic acid and butanoate ion.

i) Before addition of NaOH the pH will be calculated using Henderson Hassalbalch's equation:

pH=pKa+log\frac{[salt]}{[acid]}

pKa=-logKa=-log(1.5X10^{-5})=4.82

ii) on addition of base the pH will increase.

8 0
4 years ago
Of the major types of organic compounds found in the body, which type is used to make enzymes, to make structural molecules such
zhenek [66]

Answer:

Proteins.

Explanation:

Proteins (also called polypeptides) are large biological molecules which consists of one or more chains of amino acid. Proteins perform a series of functions which are catalysing metabolic reactions, DNA replication, providing structure to cells, transport molecules from one location to another within an organism etc.

Collagen consists of amino acids bound together to form a triple helix of elongated fibrils. It can be found in the skin, ligaments etc.

Enzymes are globular protein molecules which have the tertiary structure. They are generally rounded, "squashed" ball shape. Others include fibrous proteins which are long thin structures and are found in muscles and hair.

4 0
3 years ago
2 KClO2 (s) 0 2 KCl (s) + 3 02 (g)
Nonamiya [84]

Volume of O2 : 168 L

<h3>Further explanation</h3>

Given

Reaction

2 KClO3 (s) → 2 KCl (s) + 3 O2 (g)

5 moles of KCIO3

Required

volume of O2

Solution

From the equation, mol O2 :

= 3/2 x moles KClO3

= 3/2 x 5 moles

= 7.5 moles

Assumed at STP( 1 mol = 22.4 L) :

= 7.5 x 22.4 L

= 168 L

5 0
3 years ago
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