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Harrizon [31]
3 years ago
8

In the reaction of aluminum bromide with ionized sodium bromide which compound is the Lewis acid

Chemistry
2 answers:
slavikrds [6]3 years ago
8 0
1. What is a property of a base? You should N-O-T taste laboratory chemicals!!! I don't know why textbooks emphasize the taste of acids and bases. But that is the answer. 

<span>2. In the reaction of aluminum bromide with ionized sodium bromide, which compound is the Lewis acid? </span>
<span>What reaction??? </span>

<span>3 In a neutral solution the [H^+] is ____. </span>
<span>At 25C a solution is said to be neutral when the hydrogen ion concentration is 1.00x10^-7M. </span>

<span>4 With solutions of strong acids and strong bases, the word strong refer to ____. </span>
<span>The strength of electrolytes, including acids and bases, describes the degree to which the substance ionizes. Strong acids and bases ionize completely in water. </span>

<span>5 Which of the following pairs consists of a weak acid and a strong base? </span>
<span>a. sulfuric acid, sodium hydroxide == strong, strong </span>
<span>b.acetic acid, ammonia == weak, weak </span>
<span>c. acetic acid, sodium hydroxide* == weak, strong </span>
<span>d. nitric acid, calcium hydroxide == strong, strong </span>

<span>6. The ionization constant (K^a) of HF is 6.7 x 10^-4. Which of the following is true in a 0.1M solution of this acid? </span>
<span>a. [HF] is greater than [H^+][F^-].* == Yep </span>
<span>b. [HF] is less than [H^+][F^-]. == Nope </span>
<span>c. [HF] is equal to [H^+][F^-]. == if K=1 </span>
<span>d. [HF] is equal to [H^+][F^2-] == nonsense </span>

<span>7. The process of adding a known amount of solution of known concentration to determine the concentration of another solution is called ____. </span>
<span>The process of finding the concentration of an acid or base by neutralizing it with a known concentration of a known volume is a titration.</span>
dmitriy555 [2]3 years ago
7 0

Answer:

In the reaction of aluminum bromide with ionized sodium bromide. Aluminum bromide is the Lewis acid

Explanation:

A lewis Acid is a chemical compound that has an empty orbit in its atom composition that allows it to accept electrons from other atoms. this integration is called Lewis adduct. Ionized sodium bromide is not capable of doing that because it has no empty orbital spaces to receive electrons from aluminum bromide. Therefore, aluminum bromide is the correct answer.

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<h3><u>Answer;</u></h3>

= 12.5 Moles of CaSO3

<h3><u>Explanation</u>;</h3>

The reaction between CaCO3 and SO2 is given by the equation.

CaCO3(s) + SO2(g) → CaSO3(aq) + CO2(g)

The mole ratio between CaCO3 and SO2 is 1 : 1;

1 mole of CaCO3 reacts with 1 mole SO2 to form CaSO3 and CO2

Therefore;

<em>12.5 moles of SO2 will require 12.5 moles of CaSO3</em>

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chemist adds of a M iron(III) bromide solution to a reaction flask. Calculate the mass in grams of iron(III) bromide the chemist
Sav [38]

The question is incomplete, here is the complete question:

A chemist adds 370.0 mL of a 2.25 M iron(III) bromide solution to a reaction flask. Calculate the mass in grams of iron(III) bromide the chemist has added to the flask. Round your answer to 3 significant digits

<u>Answer:</u> The mass of iron (III) bromide is 246. grams

<u>Explanation:</u>

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 2.25 M

Molar mass of iron (III) bromide = 295.6 g/mol

Volume of solution = 370.0 mL

Putting values in above equation, we get:

2.25M=\frac{\text{Mass of solute}\times 1000}{295.6\times 370.0}\\\\\text{Mass of solute}=\frac{2.25\times 295.6\times 370.0}{1000}=246.1g

Hence, the mass of iron (III) bromide is 246. grams

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