<h3><u>Answer;</u></h3>
= 12.5 Moles of CaSO3
<h3><u>Explanation</u>;</h3>
The reaction between CaCO3 and SO2 is given by the equation.
CaCO3(s) + SO2(g) → CaSO3(aq) + CO2(g)
The mole ratio between CaCO3 and SO2 is 1 : 1;
1 mole of CaCO3 reacts with 1 mole SO2 to form CaSO3 and CO2
Therefore;
<em>12.5 moles of SO2 will require 12.5 moles of CaSO3</em>
The correct answer is: [A]: "<span>points with the same elevation" .
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D all of the above because it has all of them at the crust
The question is incomplete, here is the complete question:
A chemist adds 370.0 mL of a 2.25 M iron(III) bromide solution to a reaction flask. Calculate the mass in grams of iron(III) bromide the chemist has added to the flask. Round your answer to 3 significant digits
<u>Answer:</u> The mass of iron (III) bromide is 246. grams
<u>Explanation:</u>
To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

We are given:
Molarity of solution = 2.25 M
Molar mass of iron (III) bromide = 295.6 g/mol
Volume of solution = 370.0 mL
Putting values in above equation, we get:

Hence, the mass of iron (III) bromide is 246. grams