You haven't said what 'high' resistance or 'low' current means, so there's way not enough info to nail the statement as true or false. The most precise answer is "certainly could be but not necessarily". Anyway, the current in the circuit depends on BOTH the resistance AND the voltage. So without knowing the voltage too, you can't say anything about the current.
Answer:
A. h = 2.15 m
B.
Pb' = 122 KPa
Explanation:
The computation is shown below:
a) Let us assume the depth be h
As we know that
![Pb - Pat = d \times g \times h \\\\ ( 119 - 101) \times 10^3 = 856 \times 9.8 \times h](https://tex.z-dn.net/?f=Pb%20-%20Pat%20%3D%20d%20%5Ctimes%20g%20%5Ctimes%20h%20%5C%5C%5C%5C%20%28%20119%20-%20101%29%20%5Ctimes%2010%5E3%20%3D%20856%20%5Ctimes%209.8%20%5Ctimes%20h)
After solving this,
h = 2.15 m
Therefore the depth of the fluid is 2.15 m
b)
Given that
height of the extra fluid is
![h' = \frac{2.35 \times 10^{-3}}{ area} \\\\ h' = \frac{2.35 \times 10^{-3}} { 66.2 \times 10^{-4}}](https://tex.z-dn.net/?f=h%27%20%3D%20%5Cfrac%7B2.35%20%5Ctimes%2010%5E%7B-3%7D%7D%7B%20area%7D%20%5C%5C%5C%5C%20h%27%20%3D%20%5Cfrac%7B2.35%20%5Ctimes%2010%5E%7B-3%7D%7D%20%7B%2066.2%20%5Ctimes%2010%5E%7B-4%7D%7D)
h' = 0.355 m
Now let us assume the pressure at the bottom is Pb'
so, the equation would be
![Pb' - Pat = d \times g \times (h + h')\\\\Pb' = 856 \times 9.8 \times ( 2.15 + 0.355) + 101000](https://tex.z-dn.net/?f=Pb%27%20-%20Pat%20%3D%20d%20%5Ctimes%20g%20%5Ctimes%20%20%28h%20%2B%20h%27%29%5C%5C%5C%5CPb%27%20%3D%20856%20%5Ctimes%209.8%20%5Ctimes%20%28%202.15%20%2B%200.355%29%20%2B%20101000)
Pb' = 122 KPa