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goldenfox [79]
3 years ago
13

35 POINTSS!!! PLSSSS HELLPPP!!!

Physics
1 answer:
Crazy boy [7]3 years ago
6 0

Answer:

T

beacuse:

Energy can be transferred from one object to another by doing work. ... When work is done, energy is transferred from the agent to the object, which results in a change in the object's motion (more specifically, a change in the object's kinetic energy).

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In a collision an object experiences impulses , this impulse can be determined by
astraxan [27]

In a collision an object experiences impulses, this impulse can be determined by the product of net force exerted upon it in the specific course of time.

<u>Explanation:</u>

An object experiences impulse due to the force exerted upon it in a particular time period.

i.e.

                 \text {Impulse }=F \times \Delta t

Where,

F - Force acted upon the object

\Delta t - time interval for which the force act

According to the definition of Impulse, it is the integral of force (F) that acts upon any object over a time interval ∆t. It produces an equivalent change in the momentum and that too in the same direction as of the applied force (F).

Therefore, in order to find the impulse on an object, we have to find the force acted on it in a specific time interval.

8 0
3 years ago
A(n) 930 N crate is being pushed across a level floor by a force of 400 N at an angle of 20◦ above the horizontal. The coefficie
Nana76 [90]

Answer:

The magnitude of the acceleration of the box is 2.291\,\frac{m}{s^{2}}.

Explanation:

The free body diagram of the crate is included as attachment, whose equations of equilibrium are described below:

\Sigma F_{x} = P\cdot \cos 20^{\circ} - \mu_{k}\cdot N = \left(\frac{W}{g}\right)\cdot a

\Sigma F_{y} = P\cdot \sin 20^{\circ} + N - W = 0

From second equation of equilibrium we find an expression for the normal force and find the respective value:

N = W - P \cdot \sin 20^{\circ}

N = 930\,N - 400\cdot \sin 20^{\circ}\,N

N = 793.192\,N

Lastly, the acceleration experimented by the crate during pushing is cleared in the first equation of equilibrium and consequently calculated:

a = \frac{P\cdot \cos 20^{\circ}-\mu_{k}\cdot N}{\frac{W}{g} }

a = \frac{400\cdot \cos 20^{\circ}\,N-0.20\cdot (793.192\,N)}{\frac{930\,N}{9.807\,\frac{m}{s^{2}} } }

a = 2.291\,\frac{m}{s^{2}}

The magnitude of the acceleration of the box is 2.291\,\frac{m}{s^{2}}.

3 0
2 years ago
Mutations are avoided during replication because DNA polymerase is able to _____?
Ulleksa [173]
D. add more codes
hope this  helped
3 0
3 years ago
Read 2 more answers
Light travelling in one material enters another material in which it travels faster. The light wave will:
Free_Kalibri [48]
The light will change its direction and bend away from the normal.
8 0
3 years ago
Determine the stopping location of the prize wheel. At this moment it is centered on the number 11. It is spinning at a rate of
Goshia [24]

Answer:

The wheel spins for 11.43s. The number cannot be determined.

Explanation:

We know that initial velocity is 124.4 rpm = 13.027137522 rad/s, acceleration is -1.14 rad/s^2, and final velocity is assumed to be 0 rad/s. We are asked to find t and displacement. We use the equation \omega=\omega_0+\alpha t where \omega=0 rad/s, \omega_0=13.027 rad/s, \alpha=-1.14rad/s^2, and t=?.

Rearrange the equation to obtain \frac{\omega-\omega_0}{\alpha}=t. Plug in the numbers and solve to obtain t=11.43s.

The number of the wheel cannot be determined as we do not know the placement of numbers on the wheel.

5 0
2 years ago
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