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3 years ago

35 POINTSS!!! PLSSSS HELLPPP!!!

Physics

1 answer:

Crazy boy [7]3 years ago

6 0

Answer:

beacuse:

Energy can be transferred from one object to another by doing work. ... When work is done, energy is transferred from the agent to the object, which results in a change in the object's motion (more specifically, a change in the object's kinetic energy).

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Nancy is pushing her empty grocery cart at a rate of 1.8 m/s. 30 seconds later,

Strike441 [17]

3.Es tarde y mi taxi no llega. Estoy ____.
(5 Points)
preocupada
contenta

3 0

3 years ago

the skid marks left by the decelerating jet-powered car the spirit of america were 9600 m long before it came to a stop at 198 m

N76 [4]

Answer:

97 s

Explanation:

Given:

Δx = 9600 m

v₀ = 198 m/s

v = 0 m/s

Find: t

Δx = ½ (v + v₀) t

9600 m = ½ (0 m/s + 198 m/s) t

t = 97 s

8 0

3 years ago

Read 2 more answers

Two point charges are on the y axis. A 3.90-µC charge is located at y = 1.25 cm, and a -2.4-µC charge is located at y = −1.80 cm

ladessa [460]

Answer:

a) 1.6*10^6 V

b) 13.35*10^6 V

Explanation:

The electric potential at origin is the sum of the contribution of the two charges. You use the following formula:

$V=k\frac{q_1}{r_1}+k\frac{q_2}{r_2}$ (1)

q1 = 3.90µC = 3.90*10^-6 C

q2 = -2.4µC = -2.4*10^-6 C

r1 = 1.25 cm = 0.0125 m

r2 = -1.80 cm = -0.018 m

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

You replace all the parameters in the equation (1):

$V=k[\frac{q_1}{r_1}+\frac{q_2}{r_2}]\\\\V=(8.98*10^9Nm^2/C^2)[\frac{3.90*10^{-6}C}{0.0125m}+\frac{-2.4*10^{-6}C}{0.018m}]=1.6*10^6V$

hence, the total electric potential is approximately 1.6*10^6 V

b) For the coordinate (1.50 cm , 0) = (0.015 m, 0) you have:

r1 = 0.0150m - 0.0125m = 0.0025m

r2= 0.015m + 0.018m = 0.033m

Then, you replace in the equation (1):

$V=(8.98*10^9Nm^2/C^2)[\frac{3.90*10^{-6}C}{0.0025m}+\frac{-2.4*10^{-6}C}{0.033m}]=13.35*10^6V$

hence, for y = 1.50cm you obtain V = 13.35*10^6 V

4 0

3 years ago

Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The d

KIM [24]

Answer:

a)Car E = Car D > (Car F = Car B = Car C) > Car A

b)Car E = Car D > (Car F = Car B = Car C) > Car A

Explanation:

Car A: mass = 500 kg; speed = 10 m/s

Car B: mass = 2000 kg;speed = 5 m/s

Car C:mass = 500 kg; speed = 20 m/s

Car D: mass = 1000 kg; speed = 20 m/s

Car E:mass = 4000 kg; speed = 5 m/s

Car F: mass = 1000 kg; speed = 10 m/s

Part a) Now we know that momentum of each car is product of mass and velocity , so we will have

$P_1 = m \times v\\P_1 = (500)(10)\\P_1 = 5 \times 10^3 kg m/s$

<em>Car B:</em>

$P_2 = m v\\P_2 = (2000)(5)\\P_2 = 10^4 kg m/s$

Car C:

$P_3 = m v\\P_3 = (500)(20)\\P_3 = 10^4 kg m/s$

Car D:

$P_4 = m v\\P_4 = (1000)(20)\\P_4 = 2\times 10^4 kg m/s$

Car E:

$P_5 = m v\\P_5 = (4000)(5)\\P_5 = 2\times 10^4 kg m/s$

Car F:

$P_6 = m v\\P_6 = (1000)(10)\\P_6 = 10^4 kg m/s$

So the momentum is given as ,

Car E = Car D > (Car F = Car B = Car C) > Car A

Part b)Impulse is given as change in momentum so here we can say that final momentum of all the cars will be zero as they all stops and hence the impulse is same as initial momentum of the car

so the order of impulse from largest to least is given as

Car E = Car D > (Car F = Car B = Car C) > Car A

3 0

3 years ago

When two oppositely charged electrodes are immersed in a solution, positively charged ions are attracted to the negative electro

e-lub [12.9K]

Answer:

conductivity of solution is reduced.

Explanation:

When two oppositely charged electrodes are immersed in a solution, positively charged ions are attracted to the negative electrode and gain electrons. The negatively charged ions are attracted to the positive electrode and release electrons.

Due to the process mentioned above , the negatively charged ions are accumulated at the positive electrode and the positively charged ions are accumulated at the negative electrode . This accumulation prevents further attraction of ions at oppositely charged electrodes because the incoming ions face repulsion from already accumulated ions at electrodes. Further , it creates an emf acting in opposite direction . It reduces the current through the solution. Hence conductivity of solution is reduced.

5 0

3 years ago