Explanation:
1. Force applied on an object is given by :
F = W = mg
(a) A 160 lb human being, F = 160 lb
g = acceleration due to gravity, g = 32 ft/s²


m = 5 kg
(b) A 1.9 lb cockatoo, F = 1.9 lb


m = 0.059 kg
2. (a) A 2300 kg rhinoceros, m = 2300 kg

(b) A 22 g song sparrow, m = 22 g = 0.022 kg

Hence, this is the required solution.
1. 12.75 J
Assuming that the force applied is parallel to the ramp, so it is parallel to the displacement of the cart, the work done by the force is

where
F = 15 N is the magnitude of the force
d = 85 cm = 0.85 m is the displacement of the cart
Substituting in the formula, we get

2. 10.6 N
In this part, the cart reaches the same vertical height as in part A. This means that the same work has been done (because the work done is equal to the gain in gravitational potential energy of the object: but if the vertical height reached is the same, then the gain in gravitational potential energy is the same, so the work done must be the same).
Therefore, the work done is

However, in this case the displacement is
d = 120 cm = 1.20 m
Therefore, the magnitude of the force in this case is

Answer:
The electric field due to the right ring at a location midway between the two rings is 
Explanation:
Given that,
Radius of first ring = 5 cm
Radius of second ring = 20 cm
Charge on the left of the ring = +30 nC
Charge on the right of the ring = -30 nC
We need to calculate the electric field due to the right ring at a location midway between the two rings
Using formula of electric field
Put the value into the formula


Hence, The electric field due to the right ring at a location midway between the two rings is 
Answer:
Formation of a Precipitate
Unexpected Color Change
Formation of a Gas
Explanation:
A distorted image. :3
hope i help