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2 years ago

Please help!!!! on both of them this is physics not math

Physics

1 answer:

Lera25 [3.4K]2 years ago

3 0

Ok this is probably the easiest part in physics so lol dont panic. now the way you round is by looking at the exponent which in this case for the first one is -9 so 6.8 is gonna be 0000000068. because when you have a negative exponent you move the decimal to the west side. when you have a positive decimal you move to the east side. I will not do the second one because its best if you try to solve it so you can learn it. good luck my friend.

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A powerful motorcycle can produce an acceleration of 3.50 m/s2 while traveling at 90.0 km/h. At that speed the forces resisting

IrinaK [193]

Answer:1265 N

Explanation:

Given

acceleration of motorcycle $\left ( a\right )=3.5 m/s^2$

Velocity $\left ( v\right )=90 km/h\approx 25m/s$

Air friction and Friction $\left ( f\right )=425 N$

mass of the motorcycle with rider $\left ( m\right )=240 Kg$

Applying Forces on motorcycle

$F_{engine}-f=ma$

$F_{engine}=f+ma$

$F_{engine}=425+240\left ( 3.5\right )$

$F_{engine}=425+840=1265 N$

5 0

3 years ago

A wire is oriented along the x-axis. It is connected to two batteries, and a conventional current of 2.6 A runs through the wire

lana66690 [7]

Answer:

the magnitude of the magnetic force on the wire is 0.2298 N

Explanation:

Given the data in the question;

we know that, the magnitude of magnetic force is given as;

|F $_{mg}^>$ | = I( $B^>$ × $L^>$ )

given that

I = 2.6 A

$B^>$ = 0.17

$L^>$ = 0.52

so we substitute

|F $_{mg}^>$ | = 2.6( 0.17i" × 0.52j" )

|F $_{mg}^>$ | = 0.2298 N

Therefore, the magnitude of the magnetic force on the wire is 0.2298 N

4 0

3 years ago

Altitude means the what?

andrew-mc [135]

Answer:

the height of a object or point relation to sea level or ground level

7 0

3 years ago

A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 35.5 m/s. a) What is the coeff

postnew [5]

Answer:

The coefficient of friction present between the roadway and the wheels of the truck is <u>0.833</u>.

Explanation:

Given:

Radius of the curve (R) = 150 m

Maximum speed of truck (v) = 35.5 m/s

Let the coefficient of friction between the roadway and the wheels of the truck be "μ".

As the truck is moving around a circular curve. So, the force acting on it is centripetal force which acts in the radial inward direction towards the center of the circular curve.

The centripetal force acting on the truck is given as:

$F_c=\frac{mv^2}{R}$

Now, the friction between the roadway and the wheels of the truck is responsible for providing the necessary centripetal force. So, frictional force is equal to the centripetal force necessary for circular motion.

Frictional force is given as:

$f=\mu N$

Where, 'N' is the normal force. Since there is no vertical motion, the normal force is equal to weight of truck. So,

$N=mg$

Therefore, frictional force, $f=\mu mg$

Now, frictional force = centripetal force

$f=F_c\\\\\mu mg=\frac{mv^2}{R}\\\\\mu = \frac{v^2}{Rg}$

Plug in the given values and solve for 'μ'. This gives,

$\mu=\frac{(35\ m/s)^2}{(150\ m)(9.8\ m/s^2)}\\\\\mu=\frac{1225\ m^2/s^2}{1470\ m^2/s^2}\\\\\mu=0.833$

Therefore, the coefficient of friction present between the roadway and the wheels of the truck is 0.833

7 0

3 years ago

If the velocity of a moving object decreases from 60 m/s to 30 m/s, what happens to its momentum?

amid [387]

Hello!

momentum is p=mv so if the velocity is decreased by a factor of 2, which is 1/2 the value, then the momentum of that object will decrease by the same factorial.

Hope this helps, any questions please ask. Thank you!

6 0

3 years ago

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