Answer:
Electric potential = 0.00054 V
Explanation:
We are given;
Charge; q = 3 pC = 3 × 10^(-12) C
Radius; r = 2 cm = 0.02 m
Formula for the electric potential of this surface will be;
V = kqr
Where;
K is a constant = 9 × 10^(9) N⋅m²/C².
Thus;
V = 9 × 10^(9) × 3 × 10^(-12) × 0.02
V = 0.00054 V
Answer:
<h3>The answer is 500 kg</h3>
Explanation:
The mass of the object can be found by using the formula

v is the velocity
KE is the kinetic energy
From the question we have

We have the final answer as
<h3>500 kg</h3>
Hope this helps you
The state of matter would have to be solid