Answer:
297.33 m
Step-by-step explanation:
Answer: a = 3
Step-by-step explanation: when you multiply 6 by -3 you get -18 and if you add 16 you get -2
so the slope is -3 and the y-intercept is 16
so a*-3 + 16 = 7
by subtracting 16 on both sides you get
-3a = -9
and to get a by itself you divide -3 on both sides
a = -9/-3
a= 9/3
a = 3
Yo sup??
a.For this part just draw a triangle with sides 4,8 and 8 inches respectively.
The sides having 8 inches should make equal angle with the base side.
b.One angle is 20
The other two angles be x and y
but x=y because its an isosceles triangle
x+y+20=180
2x=160
x=80
Hope this helps.
9514 1404 393
Answer:
A. (4, 12)
Step-by-step explanation:
Adding the second equation to twice the first will eliminate y.
2(10x +2y) +(3x -4y) = 2(64) +(-36)
23x = 92 . . . . . . . . simplify
x = 4 . . . . . . . . . divide by 23
This value matches choice A: (4, 12).
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature =
= 15°c
The final temperature =
= 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × (
-
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer