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guapka [62]
3 years ago
13

Most of the dissolved substance in sea water is: hydrogen chloride nitrogen sodium ANSWER NOW! I NEED HELP ASAP! WILL GIVE BRAIN

LIEST!
Chemistry
1 answer:
VMariaS [17]3 years ago
3 0

Answer: Sodium chloride

Explanation:

Ocean water contains a number of substances. When a substance which has ionic bonds is dissolved in water it takes the form of ions.

The most common ions in ocean water are sodium and chloride. These are the ions formed when common salt, sodium chloride (NaCl) is dissolved in water.

Sodium chloride accounts for about 3% of ocean water by mass.

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The compound cobalt (II) sulfate forms a hydrate with seven water molecules per formula unit. What are the name and formula of t
irina [24]

Answer: The formula of the hydrate will be CuSO_4.7H_2O and the name of the compound is copper sulphate heptahydrate.

Explanation:

Water of crystallisation is the number of water molecules that combine chemically in definite molecular proportion with the concerned salt in the crystalline state.

The formula of the hydrate will be CuSO_4.7H_2O and the name of the compound is copper (II) sulphate heptahydrate as there are 7 molecules of water.

7 0
3 years ago
Is it necessary to know the exact volume of the unknown acid or base to be titrated?
Darina [25.2K]
Yes, It is important to know the volume of Unknown acid or base to be titrated.

Titration is carried out in order to find out the concentration (i.e. molarity) of unknown acid or base. In this process a standard solution of acid or base is taken and is titrated with known volume of of titrant. At end point (neutralization) the amount of standard titrant utilized is calculated and following formula is employed to calculate the unknown concentration of unknown solution.

                                     M₁V₁/n₁  =  M₂V₂/n₂
7 0
3 years ago
Read 2 more answers
In any engineering design problem, the first step is to understand the problem and identify one or more possible solutions. In t
Semenov [28]

Answer:

rising pressure and decreasing temperature

Explanation:

Reversible reactions have a bit practical interest, but in some cases the technological benefit or profitability of production requires a shift in the equilibrium of a reversible reaction.

Increasing pressure

With increasing pressure on this system, the concentration of substances increases. In this case, the balance will shift towards smaller volumes. On the left side of the equation, two volumes of nitrogen react with one volume of hydrogen. On the right side of the equation there are two volumes of ammonia, i.e. the number of volumes on the right side of the equilibrium reaction is less than on the left and, therefore, with increasing pressure, the reaction equilibrium will shift to the right.

Decreasing temperature

When the temperature rises, the equilibrium shifts towards the endothermic reaction, and when the temperature decreases, towards the exothermic reaction and the reaction given above is the exothermic.

5 0
3 years ago
How many moles of o2 are required for the complete reaction of 54.7 g of c2h4 to form co2 and h2o?
Hunter-Best [27]
The balanced chemical equation that illustrates this reaction is:
<span>C2H4 + 3O2 --> 2CO2 + 2H2O 
</span>
From the periodic table:
mass of carbon = 12 grams
mass of hydrogen = 1 gram
Therefore:
molar mass of C2H4 = 12(2) + 4(1) = 24 + 4 = 28 grams

number of moles = mass / molar mass
number of moles of C2H4 = 54.7 / 28 = 1.95 moles

From the balanced equation above:
3 moles of oxygen are required to react with one mole of C2H4, therefore, to know the number of moles required to react with 1.95 moles of C2H4, all you have to do is cross multiplication as follows:
number of oxygen moles = (1.95*3) / 1 = 5.85 moles
4 0
3 years ago
Read 2 more answers
If 1.50g lead(II) nitrate is reacted with 1.75g sodium chromate what is the theoretical yield of the precipitate?
egoroff_w [7]

Answer:

1.46g of PbCrO₄ are the theoretical yield

Explanation:

Theoretical yield is defined as the maximum amount of products that could be produced (Assuming a yield of 100%).

The reaction of Lead (II) nitrate with sodium chromate is:

Pb(NO₃)₂(aq) + Na₂CrO₄(aq) → PbCrO₄(s) + 2NaNO₃ (aq)

First, we need to find molar mass of each reactant in order to determine limiting reactant (As the reaction is 1:1, the reactant with the lower number of moles is the limiting reactant). The moles of the limiting reactant = moles of Lead (II) chromate (The precipitate):

<em>Moles Pb(NO₃)₂ -Molar mass: 331.21g/mol-</em>

1.50g * (1mol / 331.21g) = 4.53x10⁻³ moles Pb(NO₃)₂

<em>Moles Na₂CrO₄ -Molar mass: 161.98g/mol-</em>

1.75g * (1mol / 161.98g) = 0.0108 moles

Pb(NO₃)₂ is limiting reactant and moles of PbCrO₄ are 4.53x10⁻³ moles. The mass is:

4.53x10⁻³ moles PbCrO₄ * (323.19g / mol) =

<h3>1.46g of PbCrO₄ are the theoretical yield</h3>
7 0
3 years ago
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