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Naya [18.7K]
2 years ago
9

How does Natural selection lead to the Evolution of bacteria?

Chemistry
1 answer:
BigorU [14]2 years ago
8 0

Answer:

Bacteria can evolve quickly because they reproduce at a fast rate.

Explanation:

Bacteria can evolve quickly because they reproduce at a fast rate. Mutations in the DNA of bacteria can produce new characteristics. A random mutation might cause some bacteria to become resistant to certain antibiotics, such as penicillin.

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When the molecules of gases are heated, the average kinetic energy of the molecules increases,
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True is the answer to this
6 0
3 years ago
This element is a liquid at room temperature.<br> (A) Hg<br> (B) Th<br> (C) Na<br> (D) Cl<br> (E) Co
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A) Hg, or Mercury, is a liquid at room temperature. Hope this helps!!
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3 years ago
Read 2 more answers
An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 113 amu and 115 amu, with natural abunda
DENIUS [597]

Answer: Its average atomic mass is 114.9 amu

Explanation:

Mass of isotope 1 = 113 amu

% abundance of isotope 1 = 5% = \frac{5}{100}=0.05

Mass of isotope 2 = 115 amu

% abundance of isotope 2 = 95% = \frac{95}{100}=0.95

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(113\times 0.05)+(115\times 0.95)]

A=114.9amu

Thus its average atomic mass is 114.9 amu

5 0
3 years ago
This is a summary of the findings of an experiment
olga nikolaevna [1]
Conclusion is the answer you are looking for
5 0
3 years ago
Propane (C3H8) is widely used in liquid form as a fuel for barbecue grills and camp stoves. For 67.7 g of propane, determine the
viva [34]

Answer:

A. 1.54 mole.

B. 55.39g of carbon

Explanation:

A. Determination of the number of mole in 67.7g of C3H8.

Mass of C3H8 = 67.7g

Molar mass of C3H8 = (3x12) + (8x1) = 44g/mol

Number of mole of C3H8 =..?

Number of mole = Mass/Molar Mass

Number of mole of C3H8 = 67.7/44

Number of mole of C3H8 = 1.54 mole

B. Determination of the mass of carbon in the compound.

This is illustrated below:

The mass of C in compound can be obtained as follow:

=> 3C/C3H8 x 67. 7

=> 3x12 / 44 x 67.7

=> 36/44 x 67.7

=> 55.39g

Therefore, 55.39g of carbon is present in the compound.

5 0
3 years ago
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