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LuckyWell [14K]
3 years ago
9

The pH of a solution in which the concentration of H+ is 0.010M will be:

Chemistry
1 answer:
shusha [124]3 years ago
7 0

B: 2

If it's right plz give brainliest lol <3

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Calculate weight of anhydrous compound from remains upon dehydration of 2g copper sulphate pentahydrate
Greeley [361]

Answer:

1.28 g

Explanation:

Mass of anhydrous compound/molar mass of anhydrous compound = mass of hydrated compound/ molar mass of hydrated compound

Mass of anhydrous compound = ?

Mass of hydrated compound = 2g

Molar mass of anhydrous compound= 160 g/mol

Molar mass of hydrated compound = 250 g/mol

x/160 = 2/250

250x = 2 ×160

x= 2 × 160/250

x= 1.28 g

4 0
3 years ago
What are the similarities between a chemical change and a physical change?
Reil [10]

Answer:

Physical and chemical changes are similar because they are both caused by the interaction of two or more particles.

Explanation:

Physical and chemical changes are similar because they are both caused by the interaction of two or more particles. Physical changes occur through vibrations, impacts, and other forms of movement. Chemical changes are caused by the interaction of two or more atoms or molecules.

7 0
2 years ago
Read 2 more answers
The melting point of unknown substance A is 15°C and its boiling point is 95°C. Sketch a
Igoryamba

Answer:

Idk if this is right but i hope it helps... sorry if it's wrong

Explanation:

4 0
3 years ago
What are the two types of stoichiometry?
julsineya [31]
Two types of stoichiometry are; molar mass and coefficients from balanced equation.
8 0
3 years ago
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The reaction of hydrogen and iodine to produce hydrogen iodide has a Kc of 54.3 at 703 K. Given the initial concentrations of H2
pentagon [3]

Answer:

[HI] = 0.7126 M

Explanation:

Step 1: Data given

Kc = 54.3

Temperature = 703 K

Initial concentration of H2 and I2 = 0.453 M

Step 2: the balanced equation

H2 + I2 ⇆ 2HI

Step 3: The initial concentration

[H2] = 0.453 M

[I2] = 0.453 M

[HI] = 0 M

Step 4: The concentration at equilibrium

[H2] = 0.453 - X

[I2] = 0.453 - X

[HI] = 2X

Step 5: Calculate Kc

Kc = [Hi]² / [H2][I2]

54.3 = 4x² / (0.453 - X(0.453-X)

X = 0.3563

[H2] = 0.453 - 0.3563 = 0.0967 M

[I2] = 0.453 - 0.3563 = 0.0967 M

[HI] = 2X = 2*0.3563 = 0.7126 M

3 0
3 years ago
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