In calisthenics, the resistance is ultimately provided by __________. A. free weights B. springs and elastic bands C. gravity D.
2 answers:
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First,
where is density,
is mass, and
is volume. We can compute the volume of the roll:
When the roll is unfurled, the aluminum will be a rectangular box (a very thin one), so its volume will be the product of the given area and its thickness . Note that we're assuming the given area is not the actual total surface area of the aluminum box, but just the area of the largest face (i.e. the area of one side of the unrolled sheet of aluminum).
So we have
where is the given area, so
If we're taking significant digits into account, the volume we found would have been , in turn making the thickness
.
The given question is incomplete. The complete question is as follows.
In a nuclear physics experiment, a proton (mass kg, charge +e =
C) is fired directly at a target nucleus of unknown charge. (You can treat both objects as point charges, and assume that the nucleus remains at rest.) When it is far from its target, the proton has speed
m/s. The proton comes momentarily to rest at a distance
m from the center of the target nucleus, then flies back in the direction from which it came. What is the electric potential energy of the proton and nucleus when they are
m apart?
Explanation:
The given data is as follows.
Mass of proton = kg
Charge of proton =
Speed of proton =
Distance traveled =
We will calculate the electric potential energy of the proton and the nucleus by conservation of energy as follows.
=
where,
U =
Putting the given values into the above formula as follows.
U =
=
=
Therefore, we can conclude that the electric potential energy of the proton and nucleus is .
Answer:
<h3>The answer is 12 m/s²</h3>Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
f is the force
m is the mass
From the question we have
We have the final answer as
<h3>12 m/s²</h3>Hope this helps you