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snow_lady [41]
2 years ago
8

Friction between our feet and the surface we walk on is desirable. True False​

Physics
2 answers:
andrew-mc [135]2 years ago
7 0
The answer to the question is true.

Have a nice day
STALIN [3.7K]2 years ago
5 0

Answer:

True

Explanation:

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Which of these is
Airida [17]

Answer:c

Explanation:work is force x distance. The wall doesn’t move any distance in A so that’s not work. B involves tasks that do work but I don’t think this is what they’re going for. For a short instance while kicking a ball, your foot is applying a force to the ball which moves a distance before following its own trajectory after contact with your foot. Because the contact has a short duration and isn’t instantaneous, this is work

8 0
2 years ago
Read 2 more answers
4. A motorist travels 406 km during a 9.0 hr period. What was the average speed in km/hr and m/s?
user100 [1]

Answer:

45.11 kmph and 12.530 m/s

Explanation:

Average speed = Total distance travelled / Total time taken

406/9 gives the answer in kilometers

And we convert it to m/s by multiplying it with 1000/3600

6 0
3 years ago
A 0.210-kg metal rod carrying a current of 11.0 A glides on two horizontal rails 0.490 m apart. If the coefficient of kinetic fr
sergij07 [2.7K]

Answer:

The  magnetic field is  B = 0.0764 \ T

Explanation:

From the question we are told that  

    The mass of the metal is  m  =  0.210 \ kg

     The current is  I  =  11.0 \ A

      The distance between the rail(length of the rod ) is  d  =  0.490 \ m

      The coefficient of kinetic friction is  \mu_k  =  0.200

Generally the magnetic force is mathematically represented as

      F_b  =  B *  I  *  d

Given that the rod is moving at a constant velocity, it

=>    F_b  =  F_k

Where F_k is the kinetic frictional force which is mathematically represented as

       F_k  =  \mu_k  *  m *  g

So

    B *  I  *  d =  \mu_k  * m * g

=>   B =  \frac{\mu_k  * m * g}{I  *  d }

substituting values

=>   B =  \frac{0.200  * 0.210  * 9.8 }{ 11  *  0.490 }

=>   B = 0.0764 \ T

3 0
3 years ago
Aehaeheahsdnesrthwahweahaw
WINSTONCH [101]
Answer No explanation
5 0
3 years ago
A helicopter descends from a height of 600 m with uniform negative acceleration, reaching the ground at rest in 5.00 minutes. de
uranmaximum [27]
Given:
h = 600 m, the height of descent
t = 5 min = 5*60 = 300 s, the time of descent.

Let a =  the acceleration of descent., m/s².
Let u =  initial velocity of descent, m/s.
Let t = time of descent, s.
The final velocity is v = 0 m/s because the helicopter comes to rest on the ground.
Note that u,  v, and a are measured as positive upward.

Then
 u + at = v
(u m/s) + (a m/s²)*(t s) = 0
u = - at
u = - 300a                  (1)

Also,
u*t + (1/2)at² = -h
(um/s)*(t s) + (1/2)(a m/s²)*(t s)² = 600
ut + (1/2)at² = 600       (2)
From (1), obtain
-300a +(1/2)(a)(90000) = -600
44700a = -600
a = - 1.3423 x 10⁻² m/s²

From (1), obtain
u = - 300*(-1.3423 x 10⁻²) = 4.03 m/s

Answer:
The acceleration is 0.0134 m/s² downward.
The initial velocity is 4.0 m/s upward.

3 0
3 years ago
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