for 39g water solute dissolved at 20C = solubility ( g/ 100 g H2O ) × mass of water = ( 11g / 100g H2O ) × 39g H2O = 4.29 g
amount of solute dissolved at 30 C =
= 23 / 100 * 39 = 8.97 g
Amount of extra solute dissolved = 8.97 - 4.29 = 4.7 g
Answer:
The options are
A. a hypothesis
B. a theory
C. a research question
D. a scientific explanation
The answer is A. a hypothesis
Explanation:
A hypothesis is referred to as a brief explanation on the occurrence of an event.
In the example above using of warm water on plants was inferred to make it grow faster as hot water increases the metabolism.
Answer : The density of an object is, 
Solution : Given,
Mass of an object = 60 g
Volume of an object = 
Formula used :
Now put all the given values in this formula, we get the density of an object.
Therefore, the density of an object is,
<span>Various gases and liquids have different densities and combustion points.</span>
