Answer:
he maximum frequency occurs when the denominator is minimum
  f’= f₀  
Explanation:
This is a doppler effect exercise, where the sound source is moving
            f = fo  when the source moves towards the observer
      when the source moves towards the observer
            f ’=f_o   Alexandrian source of the observer
  Alexandrian source of the observer
the maximum frequency occurs when the denominator is minimum, for both it is the point of maximum approach of the two objects
           f’= f₀  
 
        
             
        
        
        
A hypothermia is like an idea and a theory is something you think
        
             
        
        
        
Answer:
E = 1.655 x 10⁷ N/C towards the filament 
Explanation:
Electric field due to a line charge is given by the expression 
 E = ![[tex]\frac{\lambda}{2\pi\times\epsilon_0\times r}](https://tex.z-dn.net/?f=%5Btex%5D%5Cfrac%7B%5Clambda%7D%7B2%5Cpi%5Ctimes%5Cepsilon_0%5Ctimes%20r%7D) [/tex]
[/tex]
where λ is linear charge density of line charge , r is distance of given point from line charge and ε₀ is a constant called permittivity and whose value is 
8.85 x 10⁻¹².
Putting the given values in the equation given above
 E = 
E = 1.655 x 10⁷ N/C
 
        
             
        
        
        
Answer:
The observed wavelength on Earth from that hydrogen atom is  .
. 
Explanation:
Given that,
The actual wavelength of the hydrogen atom, 
A hydrogen atom in a galaxy moving with a speed of, 
We need to find the observed wavelength on Earth from that hydrogen atom. The speed of galaxy is given by :

 is the observed wavelength
 is the observed wavelength

So, the observed wavelength on Earth from that hydrogen atom is  . Hence, this is the required solution.
. Hence, this is the required solution.