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marissa [1.9K]
3 years ago
11

.Imagine that you pushed a box, applying a force of 60 newtons, over a distance of 4 meters. how much work have you done? 15 jou

les 56 joules 64 joules 240 joules
Physics
2 answers:
erica [24]3 years ago
8 0

240 joules 60*4 =240

DaniilM [7]3 years ago
5 0
Work=force X distance
Newtons is a measurement of force
4 meters is your distance 60×4=240

240 joules
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We have that the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind is

X=0m/s

From the question we are told that

mosquito flying 2 m/s

against a 2 m/s headwind

Generally

The speed over the ground is the Flight Speed minus resistance speed

Generally the equation for the  speed over the ground  is mathematically given as

X=Flight Speed-resistance speed

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3 years ago
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A 6.0 kg box slides down an inclined plane that makes an angle of 39° with the horizontal. If the coefficient of kinetic frictio
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Answer:

(B) 1.6 m/s^2

Explanation:

The equation of the forces acting on the box in the direction parallel to the slope is:

mg sin \theta - \mu N = ma (1)

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\mu N is the frictional force, with \mu = 0.6 being the coefficient of kinetic friction, N being the normal reaction of the plane

a is the acceleration

The equation of the force along the direction perpendicular to the slope is

N-mg cos \theta =0

where mg cos \theta is the component of the weight in the direction perpendicular to the slope. Solving for N,

N=mg cos \theta

Substituting into (1), solving for a, we find the acceleration:

a=gsin \theta- \mu g cos \theta=(9.8)(sin 39^{\circ})-(0.6)(9.8)(cos 39^{\circ})=1.6 m/s^2

6 0
4 years ago
Starting fom rest, a car accelerates at a constant rate, reaching 88 km/h in 12 s. (a) What is its acceleration? (b) How far doe
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Answer:

(A)  a=2.0.37m/sec^2

(B) s = 146.664 m

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We have given car starts from the rest so initial velocity u = 0 m /sec

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We know that 1 km = 1000 m

And 1 hour = 3600 sec

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Time is given t = 12 sec

(A) From first equation of motion v = u+at

So 24.444=0+a\times 12

a=2.0.37m/sec^2

So acceleration of the car will be a=2.0.37m/sec^2

(b) From third equation of motion v^2=u^2+2as

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Which phrase describes an irregular galaxy?
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Answer:b

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