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vovikov84 [41]
3 years ago
10

HELP ASAP I HAVE A FIVE MIN DEADLINE!!!

Physics
1 answer:
eimsori [14]3 years ago
7 0
Will be praying for u lol
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A 2.5-cm-diameter parallel-plate capacitor has a 2.2 mm spacing. The electric field strength inside the capacitor is 6.0×104 V/m
vladimir2022 [97]

Explanation:

The given data is as follows.

     Separation between two plates, d = 2.2 mm = 2.2 \times 10^{-3} m

     Electric field strength inside the capacitor, E = 6.0 \times 10^{4} V/m

Therefore, we will calculate the potential difference across the capacitor as follows.

              V = Ed

                  = 6.0 \times 10^{4} V/m \times 2.2 \times 10^{-3} m

                  = 1.32 V

Thus, we can conclude that the potential difference across the given capacitor is 1.32 V.

3 0
3 years ago
Need help please... thank u​
tangare [24]

Answer:

the answer from my side is both vertical and horizontal

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a 1000kg car uses a breaking force of 10,000N to stop in two second. What is the change in momentum of the car?
gayaneshka [121]

Answer:

ΔP =  20000 N s

Explanation:

To solve this problem we use the relation between momentum and moment

         I = Δp

let's calculate the momentum

         I = ∫F dt

if we use the average force

       I = F t

       I = 10000 2

       I = 20000 N s

therefore with the first equation

        ΔP = I = 20000 N s

8 0
3 years ago
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