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12345 [234]
3 years ago
5

Scientists are investigating how well different microphones capture and record sounds. They use tools that show how loud the hig

h and low sounds are and a tool that shows how much noise is recorded along with the actual sounds. Which is a scientific question that could be included in this investigation? Which microphone captures a singer's low sounds the loudest? Which microphone sounds best for a female singing rock music? Which microphone best records high sounds and low sounds? Which microphone is usually a male singer's favorite?
Physics
1 answer:
inna [77]3 years ago
7 0

Answer:

Which microphone captures a singer's low sounds the loudest?

Explanation:

Scientific questions are the basis of any scientific experiment. An observation is followed by a scientific question. In this question, scientists are investigating how well different microphones capture and record sounds by using tools that show how loud the high and low sounds are and a tool that shows how much noise is recorded along with the actual sounds.

Hence, a scientific question should be that which will cover the whole aspect of the investigation i.e. the question should contain a general scope of the problem. Hence, a scientific question that could be included in this investigation is:

Which microphone captures a singer's low sounds the loudest?

This is because this question contains every part being investigated i.e. How different microphones capture sounds and records them (whether low or high).

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a 1500 kg car accelerates uniformly from rest to 10.0 meters per secound in 3.0 secound .what is the work done on the car in thi
zubka84 [21]

Answer:

The work done on the car is, W = 75,000 J

The power delivered by the engine, P = 25,000 watts

Explanation:

Given,

The mass of the car, m = 1500 Kg

The initial velocity of the car, u = 0

The final velocity of the car, v = 10 m

The time duration of the travel, t = 3 s

Using the first equation of motion

                     v = u + at

                     a = (v - u) / t

Substituting the given values in the above equation

                    a = (10 - 0) / 3

                       = 3.33 m/s²

Using the second equations of motion

                      s = ut + 1/2 at²

                         = 0 + 0.5 x 3.33 x 3²

                         = 15 m

The force exerted by the car

                         F = m x a

                            = 1500 Kg x 3.33 m/s²

                            = 5000 N

The work done by the car,

                          W = F x S

                               = 5000 N x 15 m

                               = 75,000 J

Hence, the work done on the car is, W = 75,000 J

The power delivered by the engine,

                            P = W / t

                                = 75,000 J / 3 s

                                 = 25,000 watts

The power delivered by the engine, P = 25,000 watts

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I believe it is vibrate
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