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12345 [234]
3 years ago
5

Scientists are investigating how well different microphones capture and record sounds. They use tools that show how loud the hig

h and low sounds are and a tool that shows how much noise is recorded along with the actual sounds. Which is a scientific question that could be included in this investigation? Which microphone captures a singer's low sounds the loudest? Which microphone sounds best for a female singing rock music? Which microphone best records high sounds and low sounds? Which microphone is usually a male singer's favorite?
Physics
1 answer:
inna [77]3 years ago
7 0

Answer:

Which microphone captures a singer's low sounds the loudest?

Explanation:

Scientific questions are the basis of any scientific experiment. An observation is followed by a scientific question. In this question, scientists are investigating how well different microphones capture and record sounds by using tools that show how loud the high and low sounds are and a tool that shows how much noise is recorded along with the actual sounds.

Hence, a scientific question should be that which will cover the whole aspect of the investigation i.e. the question should contain a general scope of the problem. Hence, a scientific question that could be included in this investigation is:

Which microphone captures a singer's low sounds the loudest?

This is because this question contains every part being investigated i.e. How different microphones capture sounds and records them (whether low or high).

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Answer:

the energy is stored in the capacitor is 0.32 μJ

Explanation:

Given;

distance of separation, d = 1 mm = 0.001 m

edge length of the square = 100 cm

potential difference across the plates, V = 12 v

let the side of the square = L

This edge length is also the diagonal of the square which makes a right angle with the side of the square.

Applying Pythagoras theorem;

L² + L² = 100²

2L² = 100²

L² = 100²/2

Note area of a square is L²

A = L² = 100²/2 = 5000 cm²

A (m²) = 5000 cm² x 1m²/(100 cm)²

A = 5000 cm² x 1m²/10000 cm²

A = 0.5 m²

Energy stored in a parallel plate capacitor, E= ¹/₂CV²

C = ε₀A/d

where;

ε₀ is permittivity of free space = 8.85 x 10⁻¹² F/m

d is the distance of separation = 0.001 m

A is the area of the plate

C = ε₀A/d =  (8.85 x 10⁻¹²)x0.5 / 0.001

C = 4425 x 10⁻¹² F

E = ¹/₂CV² = ¹/₂ x 4425 x 10⁻¹² x ( 12)²

E = 318600 x 10⁻¹² = 0.32 μJ

Therefore, the energy is stored in the capacitor is 0.32 μJ

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