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12345 [234]
3 years ago
5

Scientists are investigating how well different microphones capture and record sounds. They use tools that show how loud the hig

h and low sounds are and a tool that shows how much noise is recorded along with the actual sounds. Which is a scientific question that could be included in this investigation? Which microphone captures a singer's low sounds the loudest? Which microphone sounds best for a female singing rock music? Which microphone best records high sounds and low sounds? Which microphone is usually a male singer's favorite?
Physics
1 answer:
inna [77]3 years ago
7 0

Answer:

Which microphone captures a singer's low sounds the loudest?

Explanation:

Scientific questions are the basis of any scientific experiment. An observation is followed by a scientific question. In this question, scientists are investigating how well different microphones capture and record sounds by using tools that show how loud the high and low sounds are and a tool that shows how much noise is recorded along with the actual sounds.

Hence, a scientific question should be that which will cover the whole aspect of the investigation i.e. the question should contain a general scope of the problem. Hence, a scientific question that could be included in this investigation is:

Which microphone captures a singer's low sounds the loudest?

This is because this question contains every part being investigated i.e. How different microphones capture sounds and records them (whether low or high).

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Freezing Point Depression: Can someone explain this formula to me? ΔTf = Kfcm
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If the solution is treated as an ideal solution, the extent of freezing point depression depends only on the solute concentration that can be estimated by a simple linear relationship with the cryoscopic constant: ΔTF = KF · m · i ΔTF, the freezing point depression, is defined as TF (pure solvent) - TF (solution). KF, the cryoscopic constant, which is dependent on the properties of the solvent, not the solute. Note: When conducting experiments, a higher KF value makes it easier to observe larger drops in the freezing point. For water, KF = 1.853 K·kg/mol.[1] m is the molality (mol solute per kg of solvent) i is the van 't Hoff factor (number of solute particles per mol, e.g. i = 2 for NaCl).
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3 years ago
When the displacement of a mass on a spring is 12 a the half of the amplitude, what fraction of the mechanical energy is kinetic
Sveta_85 [38]
You know that when the displacement is equal to the amplitude (A), the velocity is zero, which implies that the kinetic energy (KE) is zeero, so the total mechanical energy (ME) is the potential energy (PE).

And you know that the potential energy, PE, is [ 1/2 ] k (x^2)

Then, use x = A, to calculate the PE in the point where ME = PE.

ME = PE = [1/2] k (A)^2.

At half of the amplitude, x = A/2 => PE = [ 1/2] k (A/2)^2

=> PE = [1/4] { [1/2]k(A)^2 } = .[1/4] ME

So, if PE is 1/4 of ME, KE is 3/4 of ME.

And the answer is 3/4


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3 years ago
B)A man walks 95 km, East, then 55 km, north. Calculate his RESULTANT
Varvara68 [4.7K]

The resultant displacement of the man is 109.77 km in the direction N60°E.

<h3>Displacement</h3>

Displacement is the distance travelled in a specified direction.

To calculate displacement, the straight line from starting point to end point of travel is taken and calculated.

<h3>Resultant displacement of the man </h3>

In the example above, a man walks 95 km, East, then 55 km, north.

The two distances form a right-angled triangle with two sides 95 and 55 units. The hypotenuse gives the resultant displacement, D.

Using Pythagoras rule:

D^2 = 95^2 + 55^2

D^2 = 12050

D = 109.77

Thus, the resultant displacement is 109.77 km

To calculate the direction:

Let the direction be y

y + x = 90°

tan x = 55/95

tanx x = 0.578

x = 30°

Then, y = 90 - 30

y = 60°

Therefore, the resultant displacement of the man is 109.77 km in the direction N60°E.

Learn more about displacement at: brainly.com/question/321442

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2 years ago
A child in a tree house uses a rope attached to a basket to lift a 24 N dog upward through a distance of 4.9 m into the house.
jenyasd209 [6]
<h3>Answer:</h3>

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<u>We are given;</u>

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  • Distance upward is 4.9 m

We are required to calculate the work done

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In this case;

Force applied is equivalent to the weight of the dog.

Work done = 24 N × 4.9 m

                  = 117.6 Joules

Hence, the work done in lifting the dog is 117.6 Joules

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Viefleur [7K]

pitch is the perceived frequency of a sound wave.


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