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charle [14.2K]
4 years ago
13

Anybody know the acceleration of the box

Physics
1 answer:
abruzzese [7]4 years ago
5 0

It looks like the diagram is telling you that there is a net force of 8 N + 4 N = 12 N pointed to the right. By Newton's second law, the magnitude of the net force <em>F</em> is equal to the mass <em>m</em> times the acceleration <em>a</em> :

<em>F</em> = <em>m</em> <em>a</em>

12 N = (4 kg) <em>a</em>

<em>a</em> = (12 N) / (4 kg)

<em>a</em> = 3 m/s²

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A 5.0 cm object is 12.0 cm from a concave mirror that has a focal length of 24.0 cm. The distance between the image and the mirr
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Answer:

The answer is 24cm

Explanation:

This problem bothers on the curved mirrors, a concave type

Given data

Object height h= 5cm

Object distance = 12cm

Focal length f=24cm

Let the image distance be v=?

Applying the formula we have

1/v +1/u= 1/f

Substituting our given data

1/v+1/12=1/24

1/v=1/24-1/12

1/v=1-2/24

1/v=-1/24

v= - 24cm

This implies that the image is on the same side as the object and it is real

7 0
3 years ago
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Give an example for each of the following, where the force:
max2010maxim [7]

Explanation:

  • A cricket player hitting the ball from opposite direction.
  • A footballer kicking ball with more force.
  • Heating of a plastic bottle.
  • Applying brake of a car.
  • rolling a stopped marble on a table.

7 0
3 years ago
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A 10kg box is sliding at 50m/s. Find the momentum
MAXImum [283]

Answer:

The momentum of the ball is 500 kg·m/s

Explanation:

The momentum is given by Mass × Velocity

The given parameters are;

The mass of the box = 10 kg

The velocity by which the box is sliding = 50 m/s

Therefore, the momentum of the ball is given as follows;

The momentum of the ball = 10 kg × 50 m/s = 500 kg·m/s

The momentum of the ball = 500 kg·m/s

5 0
3 years ago
A 2-kg toy car accelerates from 0 to 5 m/s2. It
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10 joules of work is done by the object
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Even through there is equal and opposite reaction,usually the two forces are not seen balanced.Why?
Tomtit [17]

Answer:

This may refer to a situation like:

"one person pushes a box, if there is equal and opposite reaction why the box moves and the person does not?"

Remember the second Newton's law:

F = m*a

suppose that the mass of the person is 3 times the mass of the box.

So, if the box has a mass M, the person will have a mass 3*M

Then the Newton's equation for the box when the person pushes with a force F is:

F = M*a

solving for the acceleration, we get:

F/M = a

While the person is also pushed by the box with a force with the same magnitude, then the equation for the person is:

F = (3*M)*a'

Solving for the acceleration, we get:

F/(3M) = a'

Now we can compare the acceleration of the box (F/M) with the acceleration of the person (F/3M).

Is easy to see that the acceleration of the box is 3 times the acceleration of the person.

So regardless of the fact that both the box and the person experience a force with the same magnitude, the box will move more due to this force.

This is why in situations like this, the forces do not seem balanced.

5 0
3 years ago
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